Density is the measurement of the amount of mass per unit of volume.
In this case we should calculate the density of prairie dog burrows on a square field. This is a surface charge density.It is defined as the total amount of units q per km^2.
to calculate<span> the </span>density of prairie dog burrows, we should divide the total number of prairie dog burrows in the field <span>by the size of the field. Thus,
</span><span>
</span>prairie dog <span>burrows in square kilometers= number of dog burrows/ size of the field
size of the field=0.9*0.9=900*900=180000m^2
1980/180000</span><span> m^2= 0.011 dog burrows in square meter
11 dogs in square kilometer</span>
The question is worded a bit strangely (in my opinion anyway), but I think your teacher wants you to describe how exponents work.
Let's say we had the expression ![5^3](https://tex.z-dn.net/?f=5%5E3)
The base is 5 as its the bottom most value (think of something like the base of a tree or building). The exponent is 3.
The exponent of 3 tells the reader to multiply the base 5 by itself 3 times like so
![5^3 = 5*5*5 = 125](https://tex.z-dn.net/?f=5%5E3%20%3D%205%2A5%2A5%20%3D%20125)
With larger exponents, it becomes more tedious to write out all the repeated multiplications, which is why many calculators have an exponent button to save time.
Answer:
19
Step-by-step explanation:
its just addition
I divided 315 by any random number and chose the one that gave me a whole number
So I got
![5](https://tex.z-dn.net/?f=5%20)
x
<h3>The true statement about circumference of a circle is: circumference is found by multiplying Pi by the diameter</h3>
<em><u>Solution:</u></em>
<em><u>The circumference of a circle is given as:</u></em>
![\text{circumference } = 2 \pi r](https://tex.z-dn.net/?f=%5Ctext%7Bcircumference%20%7D%20%3D%202%20%5Cpi%20r)
Where,
"r" is the radius of circle
We know that,
![diameter = 2 \times radius\\\\d = 2 \times r\\\\d = 2r](https://tex.z-dn.net/?f=diameter%20%3D%202%20%5Ctimes%20radius%5C%5C%5C%5Cd%20%3D%202%20%5Ctimes%20r%5C%5C%5C%5Cd%20%3D%202r)
<em><u>Thus the circumference can also written as:</u></em>
![\text{circumference } = 2 \pi r\\\\\text{circumference } = \pi \times d](https://tex.z-dn.net/?f=%5Ctext%7Bcircumference%20%7D%20%3D%202%20%5Cpi%20r%5C%5C%5C%5C%5Ctext%7Bcircumference%20%7D%20%3D%20%5Cpi%20%5Ctimes%20d)
Thus, the circumference is found by multiplying Pi by the diameter is correct statement