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9966 [12]
2 years ago
8

Rudy and Lynn are working delivering newspapers and magazines from a publishing company for 7 months. Rudy delivers newspapers e

very 3 days in a village. Lynn also delivers magazines every 7 days in
the same village. If the two students deliver today, when is the next time they will deliver on the same day?
Mathematics
1 answer:
valentina_108 [34]2 years ago
8 0

Answer:

They will deliver on the same day again 21 days later

Step-by-step explanation:

Multiples of 3 and 7

3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

7: 7, 14, 21, 28, 35, 42, 49

They will deliver on the same day again 21 days later

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slamgirl [31]
To solve, set up a proportion

3.25 cups            x  cups
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13 servings        28 servings

Now cross multiply

13x = 28 * 3.25

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x = 7 cups



To check your answer, use proportions again, but change the left side to 4.5 cups over 18 servings, use the same steps,  if the answer is the same as above, then the answer is correct
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Evaluate 10% of 5000
Oduvanchick [21]

Answer:

500

Step-by-step explanation:

that is the procedure above

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The square of a number exceeds that number by 12. What are the two possible solutions?
vagabundo [1.1K]
X^2=x+12
minus x+12 both sides
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Carlos Can choose from a beef or turkey burger and from a wheat or white roll. How many different burgers can he make
gulaghasi [49]

Answer:

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5 0
4 years ago
A firefighter holds a hose 3 m off the ground and directs a stream of water toward a burning building. The water leaves the hose
bija089 [108]

Answer:

a). Horizontal distance = 11.1 m

b). Maximum height = 6.2 m

c). Firefighter is 13.7 m from the house

Step-by-step explanation:

Given question is incomplete; find the complete question in the attachment.

Height of the water can be determined by the expression,

h(x) = -0.026x²+ 0.577x + 3

Here x = Horizontal distance of the from the firefighter

a). Since the stream of the water will follow a parabolic path, maximum point of the parabola will be = Vertex of the parabolic path

Horizontal distance from the firefighter at which the water achieves the maximum height = -\frac{b}{2a}

From the quadratic function,

h(x) = -0.026x²+ 0.577x + 3

a = -0.026

b = 0.577

Therefore, the horizontal distance = -\frac{0.577}{2\times (-0.02612)} = 11.05 m

                                                         ≈ 11.1 meters

b). By putting x = 11.1 in the quadratic equation,

    h(x) = -0.02612(11.1)²+ 0.577(11.1) + 3

           = -3.2182 + 6.4047 + 3

           = 6.18 m

           ≈ 6.2 m

c). For h(x) = 6 m

    6 = -0.02612x² + 0.577(x) + 3

    0.02612x² - 0.577x + 3 = 0

    From quadratic formula,

    x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

    x = \frac{0.577\pm \sqrt{(-0.577)^2-4(0.02612)(3))}}{2(0.02612)}

    x = \frac{0.577\pm\sqrt{0.019489}}{0.05224}

    x = \frac{0.577\pm0.1396}{0.05224}

    x = 13.7 m, 8.37 m

Therefore, the farthest distance of the firefighter from the house will be 13.7 m

8 0
3 years ago
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