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3 years ago

What is one value of x that makes the equation-16x^2+121=0 true

Mathematics

1 answer:

jeyben [28]3 years ago

8 0

Answer:

x = ±11/4

Step-by-step explanation:

Rewrite -16x^2+121=0 as 16x^2 - 121=0 and then as 16x^2 = 121.

Take the square root of both sides. This returns 4x = ±11, and so:

x = ±11/4

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Select all the statements that correctly describe the solutions to this system of equations.

Scrat [10]

Answer:

Step-by-step explanation:

first you have to do 6 times 3 and get 18 then you need to add 3 to that then divided that by 2 then you get your answer

7 0

3 years ago

a cell phone company charges a monthly fee plus a 0.35 for text messages sent they charge 25.00 monthly fee and your bill is 58.

riadik2000 [5.3K]

Hey,

So first we are told that they charg a fixed fee of 25:00 right?That means even if you didn’t send any text messages you still have to pay 25:00.

So first we have to subtract that 25:00 form 58.25 right?This means the rest of the bill is for text messages OK?
So he spent 33.25(this is the answer to the subtraction) on the text messages right?
And for every text he sent he was charged 0.35 right? So we have to divide 33.25 by 0.35 right?
And that gets us 95.

Now we can double check the answer by multiplieng 95 by 0.35 and adding 25.

So th answer is 95

Hope this helps !!

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3 years ago

The actual height of the Gateway Arch in St. Louis is 630 feet. A scale model of the arch is 9 inches tall. Which statement(s) a

Semmy [17]

Answer:

D. The scale factor is 1:840

Step-by-step explanation:

Make 630 ft into inches, so 7560

Then make it 9/7560, which simplifies to 1/840

6 0

3 years ago

Read 2 more answers

What is the median of the data

anyanavicka [17]

Answer:

The median of the data is 3

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

The polynomial of degree 5, P ( x ) has leading coefficient a=1, has roots of multiplicity 2 at x = 3 and x = 0 , and a root of

ser-zykov [4K]

Answer:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$ , for $r_{1} = 0$

Step-by-step explanation:

The general form of quintic-order polynomial is:

$p_{5}(t) = a\cdot x^{5} + b\cdot x^{4} + c\cdot x^{3} + d\cdot x^{2} + e \cdot x + f$

According to the statement of the problem, the polynomial has the following roots:

$p_{5} (t) = (x - r_{1})\cdot (x-3)^{2}\cdot x^{2} \cdot (x+1)$

Then, some algebraic handling is done to expand the polynomial:

$p_{5} (t) = (x - r_{1}) \cdot (x^{3}-6\cdot x^{2}+9\cdot x) \cdot (x+1)\\p_{5} (t) = (x - r_{1}) \cdot (x^{4}-5\cdot x^{3} + 3 \cdot x^{2} + 9 \cdot x)$

$p_{5} (t) = x^{5} - (5+r_{1})\cdot x^{4} + (3 + 5\cdot r_{1})\cdot x^{3} +(9-3\cdot r_{1})\cdot x^{2} - 9 \cdot r_{1}\cdot x$

If $r_{1} = 0$ , then:

$p_{5} (t) = x^{5} - 5\cdot x^{4} + 3\cdot x^{3} +9\cdot x^{2}$

5 0

3 years ago