2 years ago

What is one value of x that makes the equation-16x^2+121=0 true

Mathematics

1 answer:

jeyben [28]2 years ago

8 0

Answer:

x = ±11/4

Step-by-step explanation:

Rewrite -16x^2+121=0 as 16x^2 - 121=0 and then as 16x^2 = 121.

Take the square root of both sides. This returns 4x = ±11, and so:

x = ±11/4

You might be interested in

Classify the triangle with the given side lengths as 1,13,13

Anuta_ua [19.1K]

Answer:

isosceles triangle

Step-by-step explanation:

6 0

2 years ago

16 ÷ 8 = 2

hjlf

The answer is D. 2 x 8= 16

3 0

2 years ago

Read 2 more answers

Use parentheses to make this statement true: 8 x 4 - 2 x 3 + 8 / 2 = 25

Vladimir79 [104]

(8 times 4) - (2 times 3 = 8) divided by 2

7 0

2 years ago

Read 2 more answers

A cross section is the intersection of which two elements?

viva [34]

The answer is:

A solid and a plane.

4 0

2 years ago

Read 2 more answers

Paula’s entire family came to her birthday party. There were 17 people there. Paula’s parents bought enough mini-sandwiches for

djverab [1.8K]

Answer:

102

Step-by-step explanation:

Paula's parents bought 102 mini-sandwiches. When I multiplied 17 by 6, I got 102. To check my answer, I divided 102 by 6 and got 17.

17x6=102

102/6=17

Hope this helps:)

PLEASE MARK ME AS BRAINLIEST

3 0

1 year ago