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Sonja [21]
3 years ago
10

What is the exponent of 20

Mathematics
2 answers:
frutty [35]3 years ago
6 0
The answer to this is 0
Ilia_Sergeevich [38]3 years ago
4 0
I think it is 0 because I googled it.
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K<br> The solution is k<br> K/6+5=17<br> The solution is k=
aleksklad [387]

k=72

Explanation:

72/6=12

12+5=17

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2 years ago
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Mackenzie works as a salesperson at an electronics store and sells phones and phone accessories. Mackenzie earns a $10 commissio
LuckyWell [14K]

Answer:

Step-by-step explanation:

p=number of phones sold

a=number of accessories sold

10p+4a=126

c=7+a

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3 years ago
Help!! 50 points and brainliest!
Viktor [21]

Answer:

Second choice:

x=2t

y=4t^2+4t-3

Fifth choice:

x=t+1

y=t^2+4t

Step-by-step explanation:

Let's look at choice 1.

x=t+1

y=t^2+2t

I'm going to subtract 1 on both sides for the first equation giving me x-1=t. I will replace the t in the second equation with this substitution from equation 1.

y=(x-1)^2+2(x-1)

Expand using the distributive property and the identity (u+v)^2=u^2+2uv+v^2:

y=(x^2-2x+1)+(2x-2)

y=x^2+(-2x+2x)+(1-2)

y=x^2+0+-1

y=x^2

So this not the desired result.

Let's look at choice 2.

x=2t

y=4t^2+4t-3

Solve the first equation for t by dividing both sides by 2:

t=\frac{x}{2}.

Let's plug this into equation 2:

y=4(\frac{x}{2})^2+4(\frac{x}{2})-3

y=4(\frac{x^2}{4})+2x-3

y=x^2+2x-3

This is the desired result.

Choice 3:

x=t-3

y=t^2+2t

Solve the first equation for t by adding 3 on both sides:

x+3=t.

Plug into second equation:

y=(x+3)^2+2(x+3)

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

y=(x^2+6x+9)+(2x+6)

y=(x^2)+(6x+2x)+(9+6)

y=x^2+8x+15

Not the desired result.

Choice 4:

x=t^2

y=2t-3

I'm going to solve the bottom equation for t since I don't want to deal with square roots.

Add 3 on both sides:

y+3=2t

Divide both sides by 2:

\frac{y+3}{2}=t

Plug into equation 1:

x=(\frac{y+3}{2})^2

This is not the desired result because the y variable will be squared now instead of the x variable.

Choice 5:

x=t+1

y=t^2+4t

Solve the first equation for t by subtracting 1 on both sides:

x-1=t.

Plug into equation 2:

y=(x-1)^2+4(x-1)

Distribute and use the binomial square identity used earlier:

y=(x^2-2x+1)+(4x-4)

y=(x^2)+(-2x+4x)+(1-4)

y=x^2+2x+-3

y=x^2+2x-3.

This is the desired result.

3 0
3 years ago
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How mcuh does a toothpick weigh in grams?
olya-2409 [2.1K]
I believe 100mg.  I'm not so sure though but, you can always check google you know..
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3 years ago
Which formula represents the nth term of arithmetic sequence 2, 5, 8, 11, ... ?
german
2,5,8,11,14,17,20,23,29
6 0
3 years ago
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