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sukhopar [10]
3 years ago
7

Simplify the first expression 5(m+1)-1=

Mathematics
1 answer:
Olegator [25]3 years ago
8 0

Answer:

-0.8/ -4/5

Step-by-step explanation:

5(m+1) -1 = 0

5m +5 -1 = 0

5m +4 =0

5m= -4

m= -4/5

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In equilateral ∆ABC, points M, P, and K belong to AB , BC , and AC respectively and AM:MB = BP:PC = CK:KA = 1:3. Prove that ∆MPK
yaroslaw [1]

Answer:

See explanation

Step-by-step explanation:

In equilateral ∆ABC,

AB = BC = AC=a

m\angle A=m\angle B=m\angle C=60^{\circ}

Points M, P, and K belong to AB , BC , and AC respectively and

AM:MB = BP:PC = CK:KA = 1:3.

So,

AM = BP = CK =\dfrac{1}{4}a

MB = PC = KA =\dfrac{3}{4}a

Triangles AMK, BPM and CKP are all congruent by SAS postulate, so

MK=MP=PK

If MK=MP=PK, triangle MPK is equilateral triangle

3 0
3 years ago
Find the measure of an exterior angle of each regular polygon: 100-gon.
Gelneren [198K]
If this is a 100-gon, then not only does it have 100 sides, it also has 100 central angles.  Each one measures 360/100 = 3.6.  This is the vertex angle for each of those 100 triangles.  180 - 3.6 = 176.4, which has to be split equally between the 2 base angles.  This puts each of those at 88.2.  If you are looking for the exterior angle to each of those, it's the supplement of them. 180-88.2 = 91.8
4 0
3 years ago
Find the constant of variation for the relationship f(x)= 30x.
trasher [3.6K]
For a direct variation, f(x) = kx. Therefore, for f(x) = 30x, constant of variation (k) = 30.
3 0
4 years ago
Read 2 more answers
What is the value of the expression? −26−(6)2 Enter your answer in the box.
alexandr1967 [171]

Is it   −26−(6)^2? If so

−26−(6)^2

= -26 - 36

= - 62

If   −26−(6)2 (means 6 times 2) then

= -26 - 12

= -38

6 0
3 years ago
Read 2 more answers
Which equation can be solved by using this expression?
Marat540 [252]

<u>Answer:</u>

The correct answer option is B. 2 = 3x + 10x^2

<u>Step-by-step explanation:</u>

We are to determine whether which of the given equations in the answer options can be solved using the following expression:

x=\frac{-3 \pm\sqrt{(3)^2+4(10)(2)} }{2(10)}

Here, a = 10, b = 3 and c=-2.

These requirements are fulfilled by the equation 4 which is:

12=3x+10x^2

Rearranging it to get:

10x^2+3x-2=0

Substituting these values of a,b,c in the quadratic formula:

x= \frac{-b \pm \sqrt{b^2-4ac} }{2a}

x= \frac{-3 \pm\sqrt{(3)^2-4(10)(-2)} }{y}

3 0
3 years ago
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