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hodyreva [135]
3 years ago
9

Simplify the square root of 6 * the square root of 8

Mathematics
2 answers:
Troyanec [42]3 years ago
4 0

Answer:

Step-by-step explanation:

4√3

denis23 [38]3 years ago
4 0

Answer:

4√3

Step-by-step explanation:

The question is to simplify √6 × √8

Applying surds

√6 can be written as √2 ×√3

and

√8 can be written as √2 × √4

but √4=2

so;

√8 is 2√2

Write the whole question as

√2×√3×2√2

This can be written as

2√2×√2×√3

But you know √2×√2 = √4 =2

So, write as

2×2×√3 = 4√3

4√3 is the simplified form

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Step-by-step explanation:

hello :

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Answer:

Collin: about $401 thousand

Cameron: about $689 thousand

Step-by-step explanation:

A situation in which doubling time is constant is a situation that can be modeled by an exponential function. Here, you're given an exponential function, though you're not told what the variables mean. That function is ...

P(t)=P_0(2^{t/d})

In this context, P0 is the initial salary, t is years, and d is the doubling time in years. The function gives P(t), the salary after t years. In this problem, the value of t we're concerned with is the difference between age 22 and age 65, that is, 43 years.

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In Cameron's case, we have ...

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Sometimes we like to see these equations in a form with "e" as the base of the exponential. That form is ...

P(t)=P_{0}e^{kt}

If we compare this equation to the one above, we find the growth factors to be ...

2^(t/d) = e^(kt)

Factoring out the exponent of t, we find ...

(2^(1/d))^t = (e^k)^t

That is, ...

2^(1/d) = e^k . . . . . match the bases of the exponential terms

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So, in Collin's case, the equation for his salary growth is

k = ln(2)/15 ≈ 0.046210

P(t) = 55,000e^(0.046210t)

and in Cameron's case, ...

k = ln(2)/10 ≈ 0.069315

P(t) = 35,000e^(0.069315t)

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