The hypothesis is given as
H0: μd< 0
H1: μd > 0
<h3>How to solve for the hypothesis.</h3>
The null hypothesis is given as
H0: μd< 0
<h3>The alternative hypothesis is given as </h3>
H1: μd > 0
SWe have to find the value of s
we would use this formula s = sqrt [ (Σ(di - d)^2 / (n - 1) ]
This gives us 3.454
Next we have to determine the standard error
s / √(n)
3.454/2.8284
= 1.22
Degree of freedom = 8 - 1
= 7
t = (x1 - x2) - D / S.E
= 1.025
Find t critical at 0.10
= 1.895
P-value = 0.1697
d. Given that p value is greater thatn 0.1 we fail to reject the null hypothesis.
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Answer:
There were 30 children and 10 adults.
Step-by-step explanation:
Since they sold tickets to adults and childrens, the sum of those tickets must be equal to the total tickets that were sold, so we can mount our first equation as shown below:
adult + children = 40
Each adult ticket costs $9 and each children costs $5 and the total recieved was $240, therefore:
9*adult + 5*children = 240
We can mount the following equation system:
adult + children = 40
9*adult + 5*children = 240
We will multiply the first equation by -5 and sum both equations:
-5*adult -5*children = -200
9*adult + 5*children = 240
4*adult = 40
adult = 40 / 4
adult = 10
adult + children = 40
children = 40 - adult = 40 - 10 = 30
There were 30 children and 10 adults.
Answer:
2c -2 = Steve's age 2 years ago
Step-by-step explanation:
I know you can create an equation to solve this but its been a while since ive done this so im going to slowly write it out.
Day-1=12
2=18
3=24
4=30
5=36
6=42
7=48
8=54
9=60*
n=9
Answer:
$3841.26
Step-by-step explanation:
The first step is to find the price of a single session. 1179/31 is about $38.03. Multiplying this by 101, you get about $3841.26. Hope this helps!
