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Harrizon [31]
3 years ago
10

A sequence has three terms the term to term rule for sequence is multiple by3 and then add 7 given that the first term of the se

quence is -1 write down the value of the third term
Mathematics
1 answer:
olasank [31]3 years ago
8 0

Answer:

Step-by-step explanation:

a₁ = -1

a₂ = 3a₁ + 7 = 3(-1)+7 = 4

a₃ = 3a₂ + 7 = 3·4+7 = 19

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Which expression is equivalent to 5(w+4) when w= 9?<br> 519)<br> 9(5)<br> 5(9)+4<br> O 5(9)+20
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D

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Consider the following hypothesis test:
Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

H_0: \mu\leq50\\\\H_a:\mu> 50

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22

The null hypothesis is rejected, as z>zc and falls in the rejection region.

8 0
3 years ago
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