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3 years ago

I need help with this for an assignment.

Mathematics

1 answer:

garri49 [273]3 years ago

5 0

The true is the A why if you 13 is more of 12

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A rhombus shaped fountain has diagonals that measure 8.4 meters and 10.2 meters. What is the area of the rhombus?

pantera1 [17]

The answer is 85.68 squared

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3 years ago

Can ya'll do my math homework too pleaseee? again I'll give brainliest and be rlly happy.

RUDIKE [14]

Answer:

1. f = -9

2. x = -7

3. x = -9

4. x = -20

5. y = 7.5

Step-by-step explanation:

Hope this helps

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3 years ago

Read 2 more answers

Evaluate the expression 8p6

Margaret [11]

Answer:

Evaluate 8P6 P 6 8 using the formula nPr=n!(n−r)! P r n = n ! ( n - r ) ! . 8!(8−6)! 8 ! ( 8 - 6 ) ! Subtract 6 6 from 8 8 . 8!(2)! 8 ! ( 2 ) ! Simplify 8!(2)! 8 !

Step-by-step explanation:

evaluate" usually means to put a value in for the variable, but you don't give us a value for p. also, it is unclear if you ...

8 0

3 years ago

Lim x-1 x2 - 1/ sin(x-2)

balu736 [363]

Answer:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0$

Explanation:

Assuming the correct expression is to find the following limit:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}$

Use the property the limit of the quotient is the quotient of the limits:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}$

Evaluate the numerator:

$\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}$

Evaluate the denominator:

Since $\lim_{x \to1}sin(x-2)\neq 0$

$\frac{0}{\lim_{x \to1}sin(x-2)}=0$

4 0

2 years ago

Solve the problem down below:<br><br><br><br> ty :P

AVprozaik [17]

Answer:

the correct answer is1/4

5 0

2 years ago