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Mademuasel [1]
3 years ago
9

If a sector of a circle has a radius of 15m and an arc length of 25 meters, find the central

Mathematics
1 answer:
ozzi3 years ago
5 0

Answer:

25

Step-by-step explanation:

You might be interested in
Which expression is not a perfect square trinomial?
puteri [66]

Answer:

Remember that a perfect square trinomial can be factored into the form (a+b)^2

or (a-b)^2

Examples:

(x+2)(x+2) is a perfect sq trinomial --> x^2+4x+4

(x-3)(x-3) is a perfect sq trinomial --> x^2-6x+9

(x+2)(x-3) is not a perfect square trinomial because its not in the form (a+b)^2 or (a-b)^2

Now to answer your question,

for the first one, x^2-16x-64, you cannot factor it so it is not a perfect square trinomial

for the second one, 4x^2 + 12x + 9, you can factor that into (2x+3)(2x+3) = (2x+3)^2 so this is a perfect square trinomial

for the third one, x^2+20x+100 can be factored into (x+10)(x+10) so this is also a perfect square trinomial

for the fourth one, x^2+4x+16 cannot be factored so this is not a perfect square trinomial

Therefore, your answer is choices 2 and 3

Read more on Brainly.com - brainly.com/question/10522355#readmore

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help me please!!
Aleks04 [339]
A because the line is only going through the graph and hitting each point once
6 0
3 years ago
Help me with this question please
Lisa [10]
First find the equation of the line:

y - b = m (X - a)
y - 5 = 2/3 (X + 2)
3y - 15 = 2 (X + 2)
3y - 15 = 2x + 4
3y = 2x + 19

Then sub the y-value of A into the equation to find X.

y = 3
3(3) = 2x + 19
9 = 2x + 19
2x = 10
X = 5

And sub the X-value of B into the equation to find y.

X = -2
3y = 2(-2) + 19
3y = -4 + 19
3y = 15
y = 5
5 0
3 years ago
A model for the density δ of the earth’s atmosphere near its surface isδ=619.09−0.000097pwhere p (the distance from the center o
natta225 [31]

Answer: 3.751*10^18kg

Step-by-step explanation:

δ =619.09−0.000097p....equa1 where p (the distance from the center of the earth) is measured in meters and δ is measured in kilograms per cubic meter.

Calculating the density of air at 5km above earth surface

P = 5000m + 6370000m = 6.375*10^6m

δ = 619.09 -(.000097* 6.375*10^6)

δ = 0.715kg/m^3 = density

Since Mass = density*volume...equ2

To calculate volume of air around the spherical earth at height 5km

V = (4/3 pai R^3) - (4/3pai r^3) ...equation 3 where R =6.375*10^6m, r = 6.37*10^6

Substituting R and r in equation 2 to solve for volume of air

V = 1.085*10^21 - 1.08*10^21

V = 5.25*10^18m^3

Substituting δ and V into equation 2 to solve for mass of air

M = 0.715 * (5.25*10^18)

M = 3.751*10^18kg

8 0
3 years ago
Please answer ASAP!
andreev551 [17]

Ignore this post, I have no Idea what it is, report this so it gets taken down so someone else can answer...

6 0
3 years ago
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