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Mademuasel [1]
2 years ago
9

If a sector of a circle has a radius of 15m and an arc length of 25 meters, find the central

Mathematics
1 answer:
ozzi2 years ago
5 0

Answer:

25

Step-by-step explanation:

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Given a minimum usual value of 135.8 and a maximum usual value of 155.9, determine which (1 point) of the following values would
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Answer:  b. 134

Step-by-step explanation:

Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.

Let x denotes a usual value.

i.e.  135.8< x < 155.9

Therefore , the interval for the usual values is [135.8, 155.9] .

If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.

Let's check all options

a. 137  ,

since  135.8< 137 < 155.9

So , it is usual.

b. 134

since 134<135.8 (Minimum value)

So , it is unusual.

c. 146  

since  135.8< 146 < 155.9

So , it is usual.

d. 155  

since 135.8< 1155 < 155.9

So , it is usual.

Hence, the correct answer is b. 134 .

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Working conditions in the United States in the early 1900’s can best be described as atrocious.
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Step-by-step explanation:

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Where a, b, and c are real numbers and a ≠ 0 . The quadratic term is ax 2 , the linear term is bx, and the constant term is c. Quadratic functions have degree two. The graph of a quadratic function is called a parabola. If a < 0, then the parabola opens downward, like function g. If a > 0, then the parabola opens upward like function f. If the parabola opens upward, then the vertex is the point whose yvalue is the minimum value of f. If the parabola opens downward, then the vertex is the point whose y-value is the maximum value of f. The vertical line that goes through the vertex is called the axis of symmetry of the parabola.
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Answer:

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Step-by-step explanation:

1/4*16/1=4

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