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Svetlanka [38]
3 years ago
15

Please help due tonight

Mathematics
1 answer:
morpeh [17]3 years ago
5 0

Answer: In pretty sure the answer is C im very much sorry if its not C

have a good day!

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Choose the best description for the real number 34 over 3.
Norma-Jean [14]
The first one is irrational because it is a repeating fraction.
the third is square root of 7 is less than 14/5
the fourth is <span>negative 5 over 6, negative 5, negative 31 over 6, negative square root 26
</span>
3 0
3 years ago
Read 2 more answers
A rectangle's length is seven times its width. let w denote the rectangle's width. what polynomial represents the rectangle's ar
wolverine [178]

Length of the rectangle = 7w

Area = length * width

A = 7w^2

6 0
4 years ago
Can you please help me on my review?
dimaraw [331]

Answer:

  g(x) = -∛(x-7)

Step-by-step explanation:

Reflection in the y-axis changes the sign of x, so after this transformation, the function is ...

  g(x) = f(-x)

Then, translation 7 units to the right replaces x by (x-7), so after both transformations, the function is ...

  g(x) = f(-(x -7)) = f(-(x -7))

Using the given definition for f(x), we have ...

  g(x)=\sqrt[3]{-(x-7)}\\\\g(x)=-\sqrt[3]{x-7}

7 0
3 years ago
The table shows the results of a survey in which 10th-grade students were asked how many siblings (brothers and/or sisters) they
lesantik [10]

Answer:

<em>70%</em>

<em></em>

Step-by-step explanation:

Given

Number of Siblings:   ||    0  ||    1    ||      2     ||       3

Number of Students: ||    4  ||    18    ||    10     ||       8

Required

Determine the probability of a student having at least one but not more than 2 siblings

First, we have to determine the total number of 10th grade students

Total = 4 + 18 + 10 + 8

Total = 40

The probability of a student having at least one but not more than 2 siblings = P(1) + P(2)

Solving for P(1)

P(1) = number of students with 1 sibling / total number of students

From the given parameters, we have that:

Number of students with 1 sibling = 18

So:

P(1) = \frac{18}{40}

Solving for P(2)

P(2) = number of students with 2 siblings / total number of students

From the given parameters, we have that:

Number of students with 2 siblings = 10

So:

P(2) = \frac{10}{40}

P(1) + P(2) = \frac{18}{40} + \frac{10}{40}

Take LCM

P(1) + P(2) = \frac{18 + 10}{40}

P(1) + P(2) = \frac{28}{40}

Divide numerator and denominator by 4

P(1) + P(2) = \frac{7}{10}

P(1) + P(2) = 0.7

Convert to percentage

P(1) + P(2) = 70\%

<em>Hence, the required probability is 70%</em>

6 0
3 years ago
Question is attached could you please help me and explain how you got your answer?
vampirchik [111]
Okay so combine like terms
10x-4x= 6x
2-8= -6

6x=-6
x= -1

Now to check:
10(-1)-2=4(-1)-8
-10-2=-4-8
-12=-12
3 0
3 years ago
Read 2 more answers
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