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xz_007 [3.2K]
3 years ago
7

Use a common denominator to determine whether the ratios form a proportion.

Mathematics
1 answer:
Marysya12 [62]3 years ago
6 0
Well, the common denominator of6 and 15 would be three so you would get 2 and 3

the common denominator of 30 and 80 would be 10 and it would equal 3 and 8
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I was absent the day they taught this and my teacher refuses to teach me
julsineya [31]

Step-by-step explanation:

it's something in algebra i don't remember but basically the top number (12) has the x on the bottom which is multiplication and the bottom number (8) has addition so those tell u how ur supposed to get those numbers

so basically u need to find two numbers that add up to 8 and multiply to 12 so the factors are 6 and 2 because 6 • 2 is 12 and 6 + 2 = 8. hope this helps

7 0
2 years ago
Read 2 more answers
The null and alternative hypotheses are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed
OlgaM077 [116]

Answer:

Test is Left tailed test

Parameter tested is standard deviation

Step-by-step explanation:

We are given the hypothesis as;

Null hypothesis; H0: σ = 8.6

Alternative hypothesis; H1: σ < 8.6

Where;σ is a constant generally known in statistics as the standard deviation.

Now, it's the alternative hypothesis that will let us know whether this is left tailed, right tailed or two tailed.

Alternative hypothesis says σ < 8.6.

This means that the values of σ that satisfy this hypothesis are less than 8.6 and thus are on the left hand side of 8.6 on a number line. Thus, the shaded region in a normal distribution curve will be on the left.

Thus, it's a left tailed test

3 0
3 years ago
Do problem 6 show work i will give brainliest if ur correct.
aliina [53]

Step-by-step explanation:

they forget the last step which is to take the square root of the sum

7) a = 4

b = 17

a² + b² = c²

4²+ 17² = c²

16 + 289 = c²

305 = c²

√305 = c

17.464249196572980 = C

7 0
3 years ago
(Calculus help, 25 points, will give brainliest) Find the sum of the sigma notation below.
Andreyy89

\displaystyle\sum_{i=3}^{10}(2i-9)=2\sum_{i=3}^{10}i-9\sum_{i=3}^{10}1

Recall that

\displaystyle\sum_{i=1}^n1=n

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

Your sums start at i=3, so in order to apply these formulas directly, you need to compensate for the missing first two terms:

\displaystyle\sum_{i=3}^{10}1=\sum_{i=1}^{10}1-(1+1)=10-2=8

\displaystyle\sum_{i=3}^{10}i=\sum_{i=1}^{10}i-(1+2)=\frac{10\cdot11}2-3=52

\implies\displaystyle\sum_{i=3}^{10}(2i-9)=2\cdot52-9\cdot8=\boxed{32}

4 0
3 years ago
What are the removable discontinuities of the following function? f (x) = StartFraction x squared minus 36 Over x cubed minus 36
jeyben [28]

Answer:

the removal discontinuity of the following function at x=-6 or x=6.

Step-by-step explanation:

factoring  f(x)  = (x - 6)(x + 6)

                         ----------------

                          x(x - 6)^x + 6)

3 0
2 years ago
Read 2 more answers
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