Answer:
Actual yield = 138.94 g
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2Na + Cl₂ —> 2NaCl
Next, we shall determine the mass of Na that reacted and the mass of NaCl produced from the balanced equation. This can be obtained as follow:
Molar mass of Na = 23 g/mol
Mass of Na from the balanced equation = 2 × 23 = 46 g
Molar mass of NaCl = 23 + 35.5
= 58.5 g/mol
Mass of NaCl from the balanced equation = 2 × 58.5 = 117 g
SUMMARY:
From the balanced equation above,
46 gof Na reacted to produce 117 g of NaCl.
Next, we shall determine the theoretical yield NaCl. This can be obtained as follow:
From the balanced equation above,
46 gof Na reacted to produce 117 g of NaCl.
Therefore, 57.50 g of Na will react to produce = (57.50 × 117)/46 = 146.25 g of NaCl.
Thus, the theoretical yield of NaCl is 146.25 g
Finally, we shall determine the actual yield of NaCl. This can be obtained as follow:
Percentage yield = 95%
Theoretical yield = 146.25 g
Actual yield =?
Percentage yield = Actual yield / Theoretical yield × 100
95% = Actual yield / 146.25
Cross multiply
Actual yield = 95% × 146.25
Actual yield = 95/100 × 146.25
Actual yield = 0.95 × 146.25
Actual yield = 138.94 g
