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wel
3 years ago
15

The movement of water across a membrane is termed

Chemistry
1 answer:
katen-ka-za [31]3 years ago
5 0
The answer is diffusion
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Of the following, which is most likely to result after a farmer sprays his crops with pesticides?
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Of the following, which is most likely to result after a farmer sprays his crops with pesticides?D. A neighbor’s well tests positive for pesticides. 

Carbon dioxide is a colorless, odorless gas. Why is it considered a pollutant? 
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Is every solution also a mixture?
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A mixture consists of two or more components. a solution can consists of a solute dissolved in a solvent or two solvents mixed together, for instance. A mixture can also be two gases (CO2 and O2) mixed together or two solids mixed together (sawdust and chalk).
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4 years ago
When one mole of sodium chloride dissociates in water, it produces: 1 mole of ions ½ mole of sodium ions 2 moles of ions ½ mole
adelina 88 [10]
Dissociation of NaCl in water is given as below,

                             NaCl ₍s₎    →    Na⁺ ₍aq₎  +  Cl⁻ ₍aq₎

According to this balanced equation the moles on RHS and LHS are as,

Moles on LHS,
                           NaCl ₍s₎   =   1 Mole

Moles on RHS,
                          Na⁺ ₍aq₎   =   1 Mole

                           Cl⁻ ₍aq₎   =    1 Mole
Result:
           
<span>When one mole of sodium chloride dissociates in water, it produces 2 Moles of Ions.</span>
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3 years ago
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A helium balloon with a volume of 550mL is cooled from 305 to 265K. The pressure on the gas is reduced from 0.45 atm to 0.25 atm
Aleksandr [31]

860 mL.

<h3>Explanation</h3>

Separate this process into two steps:

  1. Cool the balloon from 305 K to 265 K.
  2. Reduce the pressure on the balloon from 0.45 atm to 0.25 atm.

What would be the volume of the balloon after each step?

After Cooling the balloon at constant pressure:

By Charles's Law, the volume of a gas is directly related to its temperature in degrees Kelvins.

In other words,

\dfrac{V_2}{V_1} = \dfrac{T_2}{T_1},

where

  • V_1 and V_2 are volumes of the same gas.
  • T_1 and T_2 are the temperatures (in degrees Kelvins) of that gas.

Rearranging,

V_2 = V_1 \cdot \dfrac{T_2}{T_1}\\\phantom{V_2} = 550 \times \dfrac{265}{305}\\\phantom{V_2} = 478 \; \text{mL}.

The balloon ended up with a lower temperature. As a result, its volume drops: V_2 < V_1.

After reducing the pressure on the balloon at constant temperature:

By Boyle's Law, the volume of a gas is inversely proportional to the pressure on this gas.

In other words,

\dfrac{V_2}{V_1} = \dfrac{P_1}{P_2},

where

  • V_1 and V_2 are volumes of the same gas.
  • P_1 and P_2 are the pressures on this gas.

Rearranging,

V_2 = V_1 \cdot \dfrac{P_1}{P_2}\\\phantom{V_2} = 478 \times \dfrac{0.45}{0.25}\\\phantom{V_2} = 860 \;\text{mL}.

There's now less pressure on the balloon. As a result, the balloon will gain in volume: V_2 > V_1.

The final volume of the balloon will be 860 \; \text{mL}.

7 0
3 years ago
What is the solution of pOH if the pH is 9.50
igomit [66]
Poh=4.50. I hope this helps
3 0
3 years ago
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