Find the least common multiple of two two-digit numbers. SHOW WORK

Mathematics

1 answer:

kenny6666 [7]3 years ago

5 0

Answer:

The LCM of 20 and 30 is 60.

Step-by-step explanation:

LCM means the least common multiple.

The LCM of two numbers means the least multiple both numbers share.

Use the listing method:

Multiples of 20:

20, 40, 60, 80, 100, ......

Multiples of 30:

30, 60, 90, 120, 150, ...

The LCM is 60 because that is the least common multiple 20 and 30 have.

Hope this helps

You might be interested in

Question 6 of 15, Step 1 of 1

OLga [1]

Answer:

3 hours

Step-by-step explanation:

369 divided by (58+65)

8 0

3 years ago

How much degrees turn in the hour hand from 4 to 8

Gala2k [10]

Answer:

120°

I just used a protractor tool lol. I looked it up afterwards as well and 120° is correct.

4 0

3 years ago

Which of the following is a valid step in the solution?

kirill115 [55]

Answer:

pretty sure the answer is the last one

Step-by-step explanation:

you put them to the 4th power to get rid of the root sign

6 0

4 years ago

Read 2 more answers

For the given functions, (a) express dw/dt as a function of t, both by using the chain rule and by expressing w in terms of t an

ch4aika [34]

By the chain rule,

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

We have

$w=7ye^x-\ln z\implies\begin{cases}\dfrac{\partial w}{\partial x}=7ye^x\\\\\dfrac{\partial w}{\partial y}=7e^x\\\\\dfrac{\partial w}{\partial z}=-\dfrac1z\end{cases}$

and

$\begin{cases}x=\ln(t^2+1)\\y=\tan^{-1}t\\z=e^t\end{cases}\implies\begin{cases}\dfrac{\mathrm dx}{\mathrm dt}=\dfrac{2t}{t^2+1}\\\\\dfrac{\mathrm dy}{\mathrm dt}=\dfrac1{t^2+1}\\\\\dfrac{\mathrm dz}{\mathrm dt}=e^t\end{cases}$