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kolezko [41]
2 years ago
15

The first five terms of a quadratic sequence are 3, 12, 25, 42, 63.

Mathematics
1 answer:
skad [1K]2 years ago
7 0

Since we know the sequence is quadratic, we expect the n-th term to have the general form

x_n = an^2 + bn + c

Plug in the first 3 known values of the sequence to form a system of equations.

x_1 = 3 = a + b + c

x_2 = 12 = 4a + 2b + c

x_3 = 25 = 9a + 3b + c

Eliminating c gives

(4a + 2b + c) - (a + b + c) = 12 - 3 \implies 3a + b = 9

(9a + 3b + c) - (a + b + c) = 25 - 3 \implies 8a + 2b = 22 \implies 4a + b = 11

Eliminating b gives

(4a + b) - (3a + b) = 11 - 9 \implies a = 2

Solving for b,c, we get

4a + b = 11 \implies b = 11-4\cdot2 = 3

a+b+c=3 \implies c=3-2-3 = -2

So, the n-th term of the sequence is

x_n = \boxed{2n^2 + 3n - 2}

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