What’s the rest of the qurstion?
Answer:
Explanation:
So you want to start by finding the area of the big square.
We know the width to the big square is 60cm. The length to the big square is
19
+
24
+
13
=
56
Big square
A
r
e
a
=
L
⋅
W
=
56
⋅
60
=
3360
Now let’s find the little square inside the bigger square. We see from the picture that the width is 34 and the length is 24cm. Using the same formula, we can find the area of the little square.
Little square
A
r
e
a
=
L
⋅
W
=
24
⋅
34
=
816
The area enclosed is the area of the big square minus the area of the little square.
3360
−
816
=
2544
So the area enclosed is
2544
c
m
2
Step-by-step explanation:

Hope that helps and hope you get better!
9514 1404 393
Answer:
r = 1/9
Step-by-step explanation:
First of all, solve the equation for r:
y = rx
y/x = r . . . . . . . divide by x
__
Since r is a constant, it will be the same for any corresponding pairs of x and y. It is convenient to choose both x and y as integers, as in the third table entry.
r = y/x = 5/45
r = 1/9 . . . . . . . . . reduced fraction
_____
<em>Additional comment</em>
It is not a bad idea to check to see that this works with other values of x and y. For the first line of the table, we have x = 11:
y = rx = (1/9)(11) = 11/9 = 1 2/9 . . . . matches the table value