3 years ago

Which second degree polynomial function has a leading coefficient of –1 and root 4 with multiplicity 2

2 answers:

6 0

Hello,

ANSWER B (x^4-3x²-4) [roots are i,-i,2,-2]

RSB [31]3 years ago

3 0

Your answer is f(x) = x4 – 3x2 – 4

Hope this helps.

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serious [3.7K]

Step-by-step explanation:

$= \frac{2 \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} }$

$= \frac{2 \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \times \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} - \sqrt{3} }$

$= \frac{ 2( \sqrt{2} - \sqrt{3} )( \sqrt{2} - \sqrt{3} )}{ { \sqrt{2} }^{2} - { \sqrt{3} }^{2} }$

$= \frac{2(2 - \sqrt{6} - \sqrt{6} - 3) }{2 - 3}$

$= \frac{2( - 1 - 2 \sqrt{6} )}{ - 1}$

$= \frac{ - 2(1 + 2 \sqrt{6} )}{ - 1}$

$= 2(1 + 2 \sqrt{6} )$

$= 2 + 4 \sqrt{6}$

6 0

2 years ago

larisa [96]

The answer is (1,-4)
Remember that the vertex is the center of the parabola.

3 0

3 years ago

guajiro [1.7K]

Answer:

From (0,0) and go down 1 and put a dot then down 4 and over to the right 1 and draw a line.

Step-by-step explanation:

Hope this helps have a nice day!

6 0

2 years ago

TEA [102]

It’s the second option

7 0

3 years ago

Damm [24]

21 IS 84% OF 25!!!!!

8 0

3 years ago