Answer:
2
Step-by-step explanation:
The "average value of function f(x) on interval [a, b] is given by:
f(b) - f(a)
ave. value = ---------------
b - a
Here f(t)=(t-2)^2.
Thus, f(b) = (b - 2)^2. For b = 6, we get:
f(6) = 6^2 - 4(6) + 4, or f(6) = 36 - 24 + 4 = 16
For a = 0, we get:
f(0) = (0 - 2)^2 = 4
Plugging these results into the ave. value function shown above, we get:
16 - 4
ave. value = ------------ = 12/6 = 2
6 - 0
The average value of the function f(t)=(t-2)^2 on [0,6] is 2.
Answer:
-1.
Step-by-step explanation:
(tanx- secx) (tanx+ secx).
= tan^2 x + tanx sec x- tanx sec x - sec^2x
= tan^2 x - sec^2 x.
But sec^2 x = 1 + tan^2 x
so tan^2 x - sec^2 x = -1
Answer:
3*10^5 or 300,000 cant remember witch one it is
Step-by-step explanation:
1.5*10^2= 150
2*10^3=2,000
150*2000=300,000
3*10^5
Answer:
I think A
Step-by-step explanation:
sorry if it is not correct hope it helps
