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3 years ago

Inches 7 inches 18 inches area

Mathematics

2 answers:

storchak [24]3 years ago

6 0

The area is just the dimensions multiplied, so multiply 7 by 18 and you get 126.

Aleksandr-060686 [28]3 years ago

4 0

Answer:

Step-by-step explanation:

7inchx18inch= 126inch

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Complete the equation of the line through (-6,-5) (−4,−4) PLZ HELP !!!

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Answer: y=1/2x−2

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3 years ago

What type of number is -2i?

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It is an imaginary number.

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3 years ago

A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$

And replacing we got:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

5 0

4 years ago

Jeremiah conducts a survey and finds that as the first variable in his survey increases, the

lapo4ka [179]

Answer:

Negative Association.

Step-by-step explanation:

Association between variables:

Association between variables can be classified as positive or negative.

Positive: Both move in the same direction, that is, either both increase or both decrease.

Negative: The variables move in opposite directions, one increases and the other decreases.

In this question:

As the first increases the second decreases, that is, they move in opposite directions, so it is a Negative Association.

4 0

3 years ago

Inches 7 inches 18 inches area​

Inches 7 inches 18 inches area