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Oliga [24]
3 years ago
13

PLEASE I NEED HELP!!!!!!!! BRAINLIEST AND POINTS!!!!!

Mathematics
1 answer:
forsale [732]3 years ago
8 0

Step-by-step explanation:

{a }^{2}  +  {b }^{2}  \:  =  {c }^{2}  \\  {10}^{2}  +  {26}^{2}  =  {c}^{2}  \\ 100 \:  +  \: 676 \:  =  \:  {c}^{2}  \\ 776 \: =   {c}^{2}  \\  c \:  = 27.9

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Sketch the graph of each equation y=-5x<br><br><br><br> for the down line it goes till -10
ycow [4]

Step-by-step explanation:

After you find y when x is the following you apply points on graph to get a straight line.

3 0
2 years ago
Please find the result !​
Sliva [168]

Answer:

\displaystyle - \frac{1}{2}

Step-by-step explanation:

we would like to compute the following limit:

\displaystyle  \lim _{x \to 0} \left( \frac{1}{  \ln(x +  \sqrt{  {x}^{2}  + 1} ) } -  \frac{1}{  \ln(x + 1) }  \right)

if we substitute 0 directly we would end up with:

\displaystyle\frac{1}{0}  -  \frac{1}{0}

which is an indeterminate form! therefore we need an alternate way to compute the limit to do so simplify the expression and that yields:

\displaystyle  \lim _{x \to 0} \left( \frac{ \ln(x + 1) -  \ln(x +  \sqrt{ {x}^{2} + 1 } }{  \ln(x +  \sqrt{  {x}^{2}  + 1} )  \ln(x + 1)  }  \right)

now notice that after simplifying we ended up with a<em> </em><em>rational</em><em> </em>expression in that case to compute the limit we can consider using L'hopital rule which states that

\rm \displaystyle  \lim _{x \to c} \left( \frac{f(x)}{g(x)}  \right)  = \lim _{x \to c} \left( \frac{f'(x)}{g'(x)}  \right)

thus apply L'hopital rule which yields:

\displaystyle  \lim _{x \to 0} \left( \frac{  \dfrac{d}{dx}  \ln(x + 1) -  \ln(x +  \sqrt{ {x}^{2} + 1 }  }{   \dfrac{d}{dx} \ln(x +  \sqrt{  {x}^{2}  + 1} )  \ln(x + 1)  }  \right)

use difference and Product derivation rule to differentiate the numerator and the denominator respectively which yields:

\displaystyle  \lim _{x \to 0} \left( \frac{ \frac{1}{x + 1}  -  \frac{1}{ \sqrt{x + 1} }  }{ \frac{ \ln(x + 1)}{ \sqrt{ {x}^{2}  + 1 }     }    +  \frac{  \ln(x +  \sqrt{x ^{2} + 1 }  }{x + 1} }  \right)

simplify which yields:

\displaystyle  \lim _{x \to 0} \left( \frac{ \sqrt{ {x}^{2} + 1  } - x - 1 }{  (x + 1)\ln(x  + 1 )  +  \sqrt{ {x}^{2}  + 1} \ln( x + \sqrt{ {x }^{2}  + 1} )   }  \right)

unfortunately! it's still an indeterminate form if we substitute 0 for x therefore apply L'hopital rule once again which yields:

\displaystyle  \lim _{x \to 0} \left( \frac{  \dfrac{d}{dx} \sqrt{ {x}^{2} + 1  } - x - 1 }{  \dfrac{d}{dx}  (x + 1)\ln(x  + 1 )  +  \sqrt{ {x}^{2}  + 1} \ln( x + \sqrt{ {x }^{2}  + 1}  )  }  \right)

use difference and sum derivation rule to differentiate the numerator and the denominator respectively and that is yields:

\displaystyle  \lim _{x \to 0} \left( \frac{  \frac{x}{ \sqrt{ {x}^{2} + 1 }  }  - 1}{      \ln(x + 1)   + 2 +  \frac{x \ln(x +  \sqrt{ {x}^{2} + 1 } ) }{ \sqrt{ {x}^{2} + 1 } } }  \right)

thank god! now it's not an indeterminate form if we substitute 0 for x thus do so which yields:

\displaystyle   \frac{  \frac{0}{ \sqrt{ {0}^{2} + 1 }  }  - 1}{      \ln(0 + 1)   + 2 +  \frac{0 \ln(0 +  \sqrt{ {0}^{2} + 1 } ) }{ \sqrt{ {0}^{2} + 1 } } }

simplify which yields:

\displaystyle - \frac{1}{2}

finally, we are done!

6 0
3 years ago
Read 2 more answers
4/5 = 28/x <br><br> x= <br> i need to know what x =
ella [17]

Answer:

Hello! :) have a good day!

x = 35

4/5 = 28/35

5 0
3 years ago
Can some one pleas help me with this
Aleksandr [31]

Answer:

Slope: 2/3

Step-by-step explanation:

Point 1: (3, -1)

Point 2: (0, -3)

y^2-y^1/x^2-x^1

-3+1/0-3 = -2/-3 =2/3

4 0
3 years ago
Water freezes at 0^\circ0
Flauer [41]

Leo's water is at a greater temperature. And Manoj's water is closer to freezing.

<h3>What is the temperature?</h3>

The temperature refers to the degree of hotness ant coldness of the substance.

Water freezes at 0 °C.

Manoj's water is 3 °C.

Leo's water is 7 °C.

Leo's water is at a greater temperature.

Manoj's water is closer to freezing.

The complete question is attached below.

More about the temperature link is given below.

brainly.com/question/11464844

#SPJ1

3 0
2 years ago
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