When multipled
cm^1 x cm^1 x cm^1 = cm^3 or cc for cubic centimeters the answer is A.
306=2*153=2*3*51=2*3*3*17
54=2*27=2*3*9=2*3*3*3,
so 306= 2*3*3*17, and 54 = 2*3*3*3
GCF we are looking for all factors that belong to both of these numbers, that are common for both numbers.
306= 2*3*3*17,
54 = 2*3*3*3
GCF = 2*3*3
LCM should include all factors that belong as first as second numbers, and we take prime factor from the number that has maximum repetition of it
306 = 2*3*3*17
54=2*3*3*3
We can see 2 - one time, 3 - 3 times , and 17 - one time
LCM =2*3*3*3*17
Product of two numbers : 306*54=(2*3*3*17) * (2*3*3*3)= 2²*2⁵*17
HCF*LCM=(2*3*3)*(2*3*3*3*17)=2²*3⁵*17
So we can see that
Product of two numbers = HCF*LCM=2²*3⁵*17
If you need you can calculate
306= 2*3*3*17,
54 = 2*3*3*3
GCF = 2*3*3=18
LCM =2*3*3*3*17=918
GCF*LCM=18*918=16524
Product of 306*54= 16524
Answer:
Step-by-step explanation:
To find recursive formula in a geometric sequence, you need to first find the common ratio, 'r', between the numbers in the given data set. From the data set given, it appears that the previous number is multiplied by 
so, r = .
Recursive formula involves two other variables:
the 
term in the sequence
=the term before the term
So, the final formula is:
Answer:
∠NXO = 90° because the diagonals of a rhombus are perpendicular. Because the sum of angles in a triangle is 180°, 90 + 29 + ∠7 = 180 which means ∠7 = 61°.
Infinitely many solutions
