5 is your answer . i hate permutations
Answer:
The student incorrectly simplified 10ab root 2a + 20a root 2a
Step-by-step explanation:
Answer:
Option D
Step-by-step explanation:
We are given the following equations -

It would be best to solve this equation in matrix form. Write down the coefficients of each terms, and reduce to " row echelon form " -
First, I swapped the first and third rows.
Leading coefficient of row 2 canceled.
The start value of row 3 was canceled.
Matrix rows 2 and 3 were swapped.
Leading coefficient in row 3 was canceled.

And at this point, I came to the conclusion that this system of equations had no solutions, considering it reduced to this -

The positioning of the zeros indicated that there was no solution!
<u><em>Hope that helps!</em></u>
<em>Let </em><em>the </em><em>two </em><em>numbers </em><em>be </em><em>3x </em><em>and </em><em>4x</em>
<em>sum </em><em>=</em><em>3x </em><em>+</em><em> </em><em>4x </em><em>=</em><em> </em><em>7x</em>
<em>7x </em><em>=</em><em> </em><em>133</em>
<em>x=</em><em> </em><em>19</em>
<em>the </em><em>numbers </em><em>are </em><em>:</em>
<em>3(</em><em>1</em><em>9</em><em>)</em><em> </em><em>=</em><em> </em><em>57</em>
<em>4(</em><em>1</em><em>9</em><em>)</em><em> </em><em>=</em><em> </em><em>76</em>