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djverab [1.8K]
2 years ago
13

The owner of a local restaurant surveyed her staff on their preference of uniform color. The results are displayed in the table

below. Which pair of samples is most representative of the preference of all the staff? VX Sample 3 Beige Blue Black Sample 1 3 7 10 Uniform Color Survey Sample 2 Beige 12 Blue 15 Black Beige Blue Black 15 18 O Sample 1 and sample 2 are most representative because they are the same size. O Sample 1 and sample 3 are most representative because the relationship between preferences is consistent. Sample 2 and sample 3 are most representative because the samples show a greater variability in preferences. None of the samples are representative because none of the values remain constant.
Mathematics
2 answers:
Serjik [45]2 years ago
7 0

Answer:

Let's get real. The answer is D: None of the samples are representative because none of the values remained constant.

Step-by-step explanation:

The numbers are 3, 12, and 7 (none are even close), then 7,5,15 (again what part of these numbers are the same), and 10,3, and 18. As you can see, when you use your eyes it is NOT A, and the correct answer is D. Thank you very much. (I appreciate Brainliest)

nignag [31]2 years ago
3 0

Answer:

A is the answer - sample 1 and sample 2 are most representative because they are the same answer.  

Step-by-step explanation:

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Step-by-step explanation:

3 0
2 years ago
Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)
Yakvenalex [24]

Answer:

\sin d = \frac{4}{7} ; \sin e = \frac{\sqrt{33} }{7}

\cos d = \frac{\sqrt{33} }{7} ; \cos e = \frac{4}{7}

\tan d = \frac{4}{\sqrt{33} } ; \tan e = \frac{\sqrt{33} }{4}

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \cos \alpha  = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \tan \alpha  = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }

__________________________________________________

According to the question ,

1) When α (alpha) = d

  • \sin d = \frac{4}{7}
  • \cos d = \frac{\sqrt{33} }{7}
  • \tan d = \frac{4}{\sqrt{33} }

2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

3 0
3 years ago
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