Answer:
- 321 adult tickets
- 227 child tickets
Step-by-step explanation:
This sort of problem is easily solved by defining a variable to be the quantity of the higher-value contributor. Here, we can let x represent the number of adult tickets. Then total revenue is ...
6.50x +3.50(548-x) = 2881
3x +1918 = 2881 . . . . . . . . . . . . eliminate parentheses, collect terms
3x = 963 . . . . . . . . . . . . . . . . . . subtract 1918
x = 321 . . . . . . . . . . . . . . . . . . . . divide by 3
548-x = 548 -321 = 227 . . . . . .number of child tickets
321 adult tickets and 227 child tickets were sold.
Answer:
$16.60 ,and you saved $66.40
Bill does because if you multiplie 10x2=20 and Val only ran 4 1/2
3x-4n-8
3x+(-4n)+(-8)
terms=3x;-4n;-8
