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zhannawk [14.2K]
3 years ago
5

Someone answerrrrrr plssss ASAP!!!!!!’

Mathematics
1 answer:
ikadub [295]3 years ago
4 0

Answer:

9. It seems he was inactive/taking a break, as the line is completely straight.

I'm not sure about the others, but I hope that helps!

Step-by-step explanation:

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Solve the equation, round number the the nearest hundredth if needed.
Elza [17]

12+6/7n=-25n   add 25n and subtract 12 on both sides

25 6/7n=-12   convert to improper fraction

181/7n=-12   multiply both sides by seven to clear the fraction

181n=-84   divide both sides by 181 to get your answer

n= -.46   hope that helps..

4 0
3 years ago
If Jose has 10 cookies and he ate 5 how many cookies does he have left
MAVERICK [17]

Answer: five

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Which represents the solution to the absolute value equation? 3|2x+4|-1=11
larisa86 [58]
The first step for absolute value equations is to isolate the expression contained within the absolute value bars:

3|2x+4|-1 = 11
3|2x+4| = 12
|2x+4| = 4

so |2x+4| is 4 units away from 0 on a number line, but we don't know in which direction -- negative or positive? you'll have two answers.

2x+4 = 4

AND

2x+4 = -4

solve both of those two step equations and you'll get

x = 0

AND

x = -4

so 0 and -4 are your solutions.
5 0
3 years ago
Dogs are inbred for such desirable characteristics as blue eye color, but an unfortunate by-product of such inbreeding can be th
sesenic [268]

Answer:

The probability that the dogs are blue eyed and deaf is 13.02%.

Step-by-step explanation:

We are given the following information in the question:

P(Blue eyes) = 31%

P(Deaf) = 38%

P(Deaf | Blue eyes) = 42%

Formula for conditional probability:

P( A|B) = \displaystyle\frac{P(A \cap B)}{P(B)}

Now, let A be the event where the dog is deaf and B be the the event where dog is blue eyed.

P( \text{ Deaf}|\text{Blue eyes}) = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{P(\text{Blue eyes})}\\\\0.42 = \displaystyle\frac{P( \text{Deaf} \cap \text{Blue eyes})}{0.31}\\\\P( \text{Deaf} \cap \text{Blue eyes}) = 0.42\times 0.31 = 0.1302 = 13.02\%

Hence, the probability that the dogs are blue eyed and deaf is 13.02%.

6 0
3 years ago
We did not find results for: A measure of​ malnutrition, called the​ pelidisi, varies directly as the cube root of a​ person's w
asambeis [7]
\bf \qquad \qquad \textit{double proportional variation}\\\\
\begin{array}{llll}
\textit{\underline{y} varies directly with \underline{x}}\\
\textit{and inversely with \underline{z}}
\end{array}\implies y=\cfrac{kx}{z}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\

\bf \begin{cases}
p=pedalisi\\
w=weight\\
s=\textit{sitting height}
\end{cases}\quad 
\begin{array}{llll}
%pelidisi, varies directly as the cube root of a​ person's weight in grams and inversely as the​ person's sitting height in centimeters.
\textit{pelidisi varies directly}\\
\textit{as cube root of weight}\\
\textit{and inversely to }\\
\textit{sitting height}
\end{array}\implies p=\cfrac{k\sqrt[3]{w}}{s}\\\\
-------------------------------

\bf \textit{we know that }
\begin{cases}
w=48,820\\
s=78.7\\
p=100
\end{cases}\implies 100=\cfrac{k\sqrt[3]{48820}}{78.7}
\\\\\\
100\cdot 78.7=k\sqrt[3]{48820}\implies \cfrac{7870}{\sqrt[3]{48820}}=k
\\\\\\
thus\qquad \boxed{p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{w}}{s}}
\\\\\\
\textit{now, what is \underline{p} when }
\begin{cases}
w=54,688\\
s=72.6
\end{cases}?\implies p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{54688}}{72.6}

now, if that value is less than 100, then the fellow is "undernourished", otherwise, is overfed.
3 0
4 years ago
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