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3 years ago

Please help the problem is in the picture provided below.

Mathematics

2 answers:

saul85 [17]3 years ago

5 0

Step-by-step explanation:

step 1. subtract, subtract (the answers are both "subtract")

step 2. The 2nd question is incorrect and even has the answer in the question.

Nadya [2.5K]3 years ago

4 0

Answer:

sorry I don't know

Step-by-step explanation:

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Convert the measurement. HELP ME ASAP

alex41 [277]

Answer:

1800 cm

Step-by-step explanation:

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3 years ago

Factor the following polynomial completely.

lapo4ka [179]

I just took this question on a test and the answer was c

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3 years ago

Read 2 more answers

Electrons execute 1.4*10^6 revolutions per sec in a magnetic field of flux density

seropon [69]

The charge of the electrons is $8.02 \times 10^{-19} \ C$ .

The given parameters:

Number of revolution of the electron, N = 1.4 x 10⁶ rev per sec
Flux density, B = 10⁻⁵ T
Mass of electron, m = 9.11 x 10⁻³¹ kg

The angular speed of the electron is calculated as follows;

$\omega = 2\pi N\\\\\omega = 2\pi \ \frac{rad}{1 \ rev} \times 1.4 \times 10^6 \ rev/s\\\\\omega = 8.798 \times 10^6 \ rad/s$

The charge of the electrons is calculated as follows;

$F_c= m\omega ^2 r\\\\F_{B}= qvB = q\omega r B \\\\F_c = F_B\\\\m\omega ^2 r = q\omega r B \\\\q = \frac{m\omega ^2 r}{\omega r B} \\\\q = \frac{m \omega }{B} \\\\q = \frac{9.11 \times 10^{-31} \times 8.798 \times 10^6}{10^{-5}} \\\\q = 8.02 \times 10^{-19} \ C$

The charge of the electrons is $8.02 \times 10^{-19} \ C$ .

The complete question here:

Electrons execute 1.4*10^6 revolutions per sec in a magnetic field of flux density 10⁻⁵ T. What will be the value of charge of the electron?

Learn more about magnetic force of electrons here: brainly.com/question/3990732

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2 years ago

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natita [175]

What about it? uhhhh

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2 years ago

find the point-slope equation of the line perpendicular to the line y=2x+5 passing through the point (1,4). (please include solu

pishuonlain [190]

First off, let's keep in mind that perpendicular lines have negative reciprocal slopes, hmmm so what's the slope of y = 2x + 5?

well, notice, that equation is in slope-intercept form, thus $\bf y=\stackrel{slope}{2}x+5$ .

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}}
{2\implies \stackrel{slope}{\cfrac{2}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{2}}}$

so, we're really looking for the equation of a line whose slope is -1/2 and runs through 1,4.

$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad \qquad \qquad 
slope = m\implies -\cfrac{1}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-4=-\cfrac{1}{2}(x-1)$

7 0

3 years ago