Subtract them left to right
Answer:
below
Step-by-step explanation:
76.98
To Find Surface Area:
So Surface area is found according to this equation SA=2lw+2lh+2hw
6and 1/2 times 2 is 13 that would be the 2 sides
then you do 3 times 6 1/2 which is 19 1/2, which is the top and bottom
finally you do 3 times 9 1/5 which is 27 3/5.
Now since 1/2 and 1/5 are not the same, we find the LCM or Least Common Multiple, which is 10 so 1/2 is multiplied by 5 which is 5/10 and 3/5 is multiplied by 2 which makes 6/10.
Adding 5/10 and 6/10 is 11/10 or 1 1/10
13+6+9=28
28+1 1/10 = 29 1/10
and finally because we did surface area it is 29 1/10 CM^2
__________________________________________________________
To Find Volume:
The Equation used to find volume is l*w*h
The Length is 6 1/2
Height is 9 1/5
width is 3
First, lets again convert the fractions
5/10 and 6/10
6 5/10 times 9 6/10 is 62.4
62.4 times 3 is 187.2
The .2 and be put into 2/10 or 1/5 so the FINAL answer is 187 1/5
Another way to check this is
6*9*3=162
1/5*1/2
Hope this helped :)
~Ukiahsmith1
Answer:
On occasions you will come across two or more unknown quantities, and two or more equations
relating them. These are called simultaneous equations and when asked to solve them you
must find values of the unknowns which satisfy all the given equations at the same time.
Step-by-step explanation:
1. The solution of a pair of simultaneous equations
The solution of the pair of simultaneous equations
3x + 2y = 36, and 5x + 4y = 64
is x = 8 and y = 6. This is easily verified by substituting these values into the left-hand sides
to obtain the values on the right. So x = 8, y = 6 satisfy the simultaneous equations.
2. Solving a pair of simultaneous equations
There are many ways of solving simultaneous equations. Perhaps the simplest way is elimination. This is a process which involves removing or eliminating one of the unknowns to leave a
single equation which involves the other unknown. The method is best illustrated by example.
Example
Solve the simultaneous equations 3x + 2y = 36 (1)
5x + 4y = 64 (2) .
Solution
Notice that if we multiply both sides of the first equation by 2 we obtain an equivalent equation
6x + 4y = 72 (3)
Now, if equation (2) is subtracted from equation (3) the terms involving y will be eliminated:
6x + 4y = 72 − (3)
5x + 4y = 64 (2)
x + 0y = 8
56 I think :) tell me if it is
