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3 years ago

9

PLZ HURRY PICTURE IS THERE

1 answer:

Sladkaya [172]3 years ago

7 0

Answer:

area of circle=4/3 π4²=67cm²

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James estimated the total cost of groceries to be $50. The actual cost of the groceries is $65. What is the percent error? Round

Yuki888 [10]

The percentage error is 23%

Explanation:

The estimated total cost of the groceries = $50

The actual cost of the groceries = $65

To find the error value, we need to subtract the value of actual cost and total cost of the groceries.

Thus,

error value = actual cost - total cost

error value $= 65-50=15$

Hence, error value = $15

The formula to determine the percent error is given by

$Percent error $=\left(\frac{\text { error value}}{\text {actual value}}\right) \times 100$$

Substituting the values in the formula, we get,

$\begin{aligned} \text { Percent error } &=\left(\frac{15}{65}\right) \times 100 \\ &=0.231 \times 100 \\ &=23.1 \end{aligned}$

Rounding off the value, we have, 23%

Thus, the percentage error is 23%

6 0

3 years ago

A ladder is placed 30 inches from a wall. It touches the wall at a height of 50 inches from the ground. The angle made by the la

Alex73 [517]

The degree measure is about 59° and the length of the ladder is 10√34 in or about 59.3in

3 0

3 years ago

Simplify: −3 • −26<br><br> A. −78<br> B. −68<br> C. 68<br> D. 78

hammer [34]

-3 x -26 = 78

meaning the answer is D.

The reason the answer is D, is because two negatives when multiplied or divided become positive. Only when multiplied or divided does this occur.

3 0

2 years ago

There are 40 GT students going on a field trip. Each one pays their teacher $8.75 to cover admission to the museum and lunch. Ad

Norma-Jean [14]

Step-by-step explanation:

There are 40 DuBois students going on a field trip.

Each one pays their teacher $8.75 to cover admission to the museum and lunch.

Admission for the students is $120 and each one gets an equal amount to spend on lunch.

To Find :

How much will each DuBois student be able to spend on lunch.

Solution :

Amount they paid for admission :

\begin{gathered}P =\$ \dfrac{120}{40}\\\\P=\$3\end{gathered}P=$40120P=$3

Now, amount of money to spend on lunch is 8.75 -8.75−3 = $5.75 .

Hence, this is the required solution.

3 0

3 years ago

Explain how to write a quadratic equation given the following three points on the graph (5,31) (3,11) (0,11)

masha68 [24]

Given:

The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).

To find:

The equation of the quadratic function.

Solution:

A quadratic function is defined as:

$y=ax^2+bx+c$ ...(i)

It is passes through the point (0,11). So, substitute $x=0,y=11$ in (i).

$11=a(0)^2+b(0)+c$

$11=c$

Putting $c=11$ in (i), we get

$y=ax^2+bx+11$ ...(ii)

The quadratic function passes through the point (5,31). So, substitute $x=5,y=31$ in (ii).

$31=a(5)^2+b(5)+11$

$31-11=a(25)+5b$

$20=25a+5b$

Divide both sides by 5.

$4=5a+b$ ...(iii)

The quadratic function passes through the point (3,11). So, substitute $x=3,y=11$ in (ii).

$11=a(3)^2+b(3)+11$

$11-11=a(9)+3b$

$0=9a+3b$

Divide both sides by 3.

$0=3a+b$ ...(iv)

Subtracting (iv) from (iii), we get

$4-0=5a+b-3a-b$

$4=2a$

$\dfrac{4}{2}=a$

$2=a$

Putting $a=2$ in (iv), we get

$0=3(2)+b$

$0=6+b$

$-6=b$

Putting $a=2,b=-6$ in (ii), we get

$y=(2)x^2+(-6)x+11$

$y=2x^2-6x+11$

Therefore, the required quadratic equation is $y=2x^2-6x+11$ .

7 0

3 years ago