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nikklg [1K]
3 years ago
6

How do you do letter c?

Mathematics
1 answer:
Helga [31]3 years ago
6 0

Answer:

1056

Step-by-step explanation:

dP/dt = 0.0013P (1 − P/6200)

Euler's method states:

yₙ₊₁ = yₙ + Δt F(tₙ, yₙ)

Substituting:

P(t+1) = P(t) + (1) [0.0013 P(t) (1 − P(t)/6200)]

P(t+1) = P(t) + 0.0013 P(t) (1 − P(t)/6200)

We know that when t=0, P=1000.

P(1) = P(0) + 0.0013 P(0) (1 − P(0)/6200)

P(1) = 1000 + 0.0013 (1000) (1 − 1000/6200)

P(1) = 1001.1

Repeating the pattern, we get P(50) is:

P(50) = 1055.7

Rounded to the nearest whole number, P(50) = 1056.

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Step-by-step explanation:

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3 years ago
Rick bought 3 shirts for $18.75 each, 2 pair of socks for $3.99 a pair, and a pair of slacks for $45.00. The
SIZIF [17.4K]

Answer:

3 shirt=3×$18.75

=56.25

2 pair shocks =3.99×2

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1 pair slacks=45.00

total=109.25

tax=6.75% then;

109.25+6.25%×109.25

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109.25+6.28

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5 0
3 years ago
A bottle and its cork cost $1.20 of the bottle costs $1.10 more than the cork. What is the cost of bottle and of the cost of cor
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8 0
3 years ago
Please help me out !!!!
Mkey [24]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Leona has a bag containing letter tiles. Which describes dependent events?
serious [3.7K]

Answer:

a) removing a vowel, not replacing it, and then removing another vowel

Step-by-step explanation:

This question is from the topic Probability. In Probability, a dependent event is one in which the outcome of one event alters or changes the outcome of another event. <u>A classic example of this is seen when sampling without replacement is done</u>. When sampling without replacement is done, the outcome of another event within the same set changes. When sampling with replacement is done, the outcome of the events are independent because every item in the population still has an equal chance of being chosen. However, in the case of sampling without replacement, once an item has been selected from a population, the outcome of every other event after it is altered based on the item that was initially chosen.

Let's assume that the bag has 26 tiles (one for each alphabet from a - z)

Population = 26, consonant = 21, vowel = 5

If a vowel or consonant is removed & is replaced, we have:

Pr (choosing "a") = number of item ÷ population

Pr = 1 ÷ 26 = 1/26

Pr (choosing "y") = 1 ÷ 26 = 1/26

Doing this for over & over again, produces the same probability

However, if an item was selected without replacement, we have:

Pr (choosing "a") = 1 ÷ 26 = 1/26

Without replacement implies that if I choose tile letter "a", tile letter "a" will not be included in subsequent events, hence:

Population = 25

Pr (choosing "u") = 1 ÷ 25 = 1/25

Without replacement, population = 24

Pr (choosing "y") = 1 ÷ 24 = 1/24

So, we see the dependent nature of the events in how that the outcome of the next event is being altered. <u>As such, </u><u>option a</u><u> describes a dependent event & is the correct answer</u>

8 0
3 years ago
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