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2 years ago

Find the cost in cents of 1.7kg of potatoes at 70 #per kg

1 answer:

8 0

What is the unit of currency here? " # " does not represent any currency, but rather is a representation of "pound" (the unit of weight, not the British pound).

If you do mean "British pound," then

70 British pounds
------------------------ = 41.2 pence (like pennies) per kg.
1.7 kg

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You are running a fuel economy study. One of the cars you find is blue. It can travel 30 1/2 miles on 1 1/4 of gasoline. Another

Furkat [3]

You are running a fuel economy study. One of the cars you find is blue. It can travel 30 and one half miles30 1 2 miles on 1 and one fourth gallons1 1 4 gallons of gasoline. Another car is red. It can travel 25 and three fifths miles25 3 5 miles on four fifths gallon 4 5 gallon of gasoline. What is the unit rate for miles per gallon for each car? Which car could travel the greater distance on 1 gallon1 gallon of gasoline?

Blue car: 30.5 / 1.25 =24.4 miles per gallon

Red car: 25.6/0.80 =32 miles per gallon

You can easily see that the Red car travel farther on 1 gallon of gasoline.

4 0

2 years ago

Adriana is planning to ride the public bus to and from school this year. She wants to figure out how much it will cost her. The

lutik1710 [3]

Answer:

C is the dependent variable and r is independent

Step-by-step explanation:

Adriana can ride the bus any number of times she wants. No one is stopping her from doing that so 'r' becomes an independent quantity.

Whereas, the total cost for the bus rides depends on the number of times Adriana rides the bus and the relation is given as, C=1.25r

This is because it costs $1.25 each time she rides the bus in one direction

4 0

2 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

NeX [460]

Answer:

(a) 0.343

(b) 0.657

(d) 0.216

(e) 0.353

Step-by-step explanation:

Let P(a vehicle passing the test) = p

$p = \frac{70}{100} = 0.7$

Let P(a vehicle not passing the test) = q

q = 1 - p

q = 1 - 0.7 = 0.3

(a) P(all of the next three vehicles inspected pass) = P(ppp)

= 0.7 × 0.7 × 0.7

= 0.343

(b) P(at least one of the next three inspected fails) = P(qpp or qqp or pqp or pqq or ppq or qpq or qqq)

= (0.3 × 0.7 × 0.7) + (0.3 × 0.3 × 0.7) + (0.7 × 0.3 × 0.7) + (0.7 × 0.3 × 0.3) + (0.7 × 0.7 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.3)

= 0.147 + 0.063 + 0.147 + 0.063 + 0.147 + 0.063 + 0.027

= 0.657

= (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.063 + 0.063 + 0.063

= 0.189

(d) P(at most one of the next three vehicles inspected passes) = P(pqq or qpq or qqp or qqq)

= (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7) + (0.3 × 0.3 × 0.3)

= 0.063 + 0.063 + 0.063 + 0.027

= 0.216

(e) Given that at least one of the next 3 vehicles passes inspection, what is the probability that all 3 pass (a conditional probability)?

P(at least one of the next three vehicles inspected passes) = P(ppp or ppq or pqp or qpp or pqq or qpq or qqp)

= (0.7 × 0.7 × 0.7) + (0.7 × 0.7 × 0.3) + (0.7 × 0.3 × 0.7) + (0.3 × 0.7 × 0.7) + (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.343 + 0.147 + 0.147 + 0.147 + 0.063 + 0.063 + 0.063

= 0.973

With the condition that at least one of the next 3 vehicles passes inspection, the probability that all 3 pass is,

$= \frac{P(all\ of\ the\ next\ three\ vehicles\ inspected\ pass)}{P(at\ least\ one\ of\ the\ next\ three\ vehicles\ inspected\ passes)}$

$= \frac{0.343}{0.973}$

= 0.353

3 0

3 years ago

Read 2 more answers

Evaluate sigma 12 n=3-5n-1

Leni [432]

12n = 3-5n-1 or n =3-5n-1???

6 0

2 years ago

I need the set up and I'm solving for x, please help.

lawyer [7]

I think it is X equals 20 because there’s 180 degrees I a triangle and 100+40= 140 and you have e 40 remaining and since it’s 2x you do 40 divided by 2 which is 20 do the inverse to check

7 0

2 years ago

Read 2 more answers