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2 years ago

Whats the answer to 10/y = 2/9

Mathematics

2 answers:

aleksley [76]2 years ago

6 0

Answer:

y=45

Step-by-step explanation:

pav-90 [236]2 years ago

3 0

Answer:

=45

Step-by-step explanation:

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The HCP prescribes methotrexate 7.5 mg PO weekly, in 3 divides doses for a child with rheumatoid arthritis whose body surface ar

dexar [7]

Answer:

1.5mg

Step-by-step explanation:

From the question, we are told that the HCP prescribed 7.5 mg of PO weekly

The therapeutic dosage is given in the question as 5 - 15 mg/m² weekly.

The child's body surface area is given = 0.6m²

The mg of PO that the nurse should administer in each of the three doses given weekly is calculated as

7.5mg/ 5mg/m²

= 1.5 mg of PO

4 0

3 years ago

78000 rounded to the nearest ten thousand

GenaCL600 [577]

78,000 rounded to the nearest ten thousand is 80,000.

8 0

3 years ago

What do you get when you put 1 and 1 together?!!?

chubhunter [2.5K]

Two !!!! ... unless this is some riddle and there's a huge in depth meaningful answer i'm unaware about o.O

7 0

3 years ago

I need help pls help

Snezhnost [94]

Answer:

Step-by-step explanation:

hope this helps

3 0

2 years ago

Read 2 more answers

Find the product of all real values of r for which 1/2x=r-x/7

Dahasolnce [82]

Answer:

$r = \±\sqrt{14$

$Product = -14$

Step-by-step explanation:

Given

$\frac{1}{2x} = \frac{r - x}{7}$

Required

Find all product of real values that satisfy the equation

$\frac{1}{2x} = \frac{r - x}{7}$

Cross multiply:

$2x(r - x) = 7 * 1$

$2xr - 2x^2 = 7$

Subtract 7 from both sides

$2xr - 2x^2 -7= 7 -7$

$2xr - 2x^2 -7= 0$

Reorder

$- 2x^2+ 2xr -7= 0$

Multiply through by -1

$2x^2 - 2xr +7= 0$

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

$b^2 - 4ac = 0$

For a quadratic equation

$ax^2 + bx + c = 0$

By comparison with $2x^2 - 2xr +7= 0$

$a = 2$

$b = -2r$

$c =7$

Substitute these values in $b^2 - 4ac = 0$

$(-2r)^2 - 4 * 2 * 7 = 0$

$4r^2 - 56 = 0$

Add 56 to both sides

$4r^2 - 56 + 56= 0 + 56$

$4r^2 = 56$

Divide through by 4

$r^2 = 14$

Take square roots

$\sqrt{r^2} = \±\sqrt{14$

$r = \±\sqrt{14$

Hence, the possible values of r are:

$\sqrt{14$ or $-\sqrt{14$

and the product is:

$Product = \sqrt{14} * -\sqrt{14}$

$Product = -14$

8 0

3 years ago