Answer:
I gotchu the answer is 47
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<span>12.6≤<span>g+17.4</span></span> Flip the equation.<span><span> g+17.4</span>≥12.6</span> Subtract 17.4 from both sides.<span><span><span> g+17.4</span>−17.4</span>≥<span>12.6−17.4</span></span><span> g≥<span>−4.8</span></span> Answer: <span>g≥<span>−<span>4.8</span></span></span>
The solutions appear to be
{π/2, 2π/3, 4π/3}.
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Replacing sin(2x) with 2sin(x)cos(x), you have
2sin(x)cos(x) +sin(x) -2cos(x) -1 = 0
sin(x)(2cos(x) +1) -(2cos(x) +1) = 0 . . . . factor by grouping
(sin(x) -1)(2cos(x) +1) = 0
This has solutions
sin(x) = 1
x = π/2and
2cos(x) = -1
cos(x) = -1/2
x = {2π/3, 4π/3}
Answer:
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Step-by-step explanation: