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skelet666 [1.2K]
3 years ago
8

Is this relation a function

Mathematics
1 answer:
bulgar [2K]3 years ago
7 0

Answer:

the answer is A. you use the vertical line test

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Which is the completely factored form of 4x3 10x2 – 6x? 2(x 3)(2x – 1) 2x(x 3)(2x – 1) 2x(x – 3)(2x – 1) 2(x – 3)(2x 1).
Natalija [7]

The equation 4x^3+10x^2 – 6x is factorized as 2x(x+3)(2x – 1).

Option B represents the correct factors of the equation.

<h3>What is a Factor of the number?</h3>

A factor of the number can be defined as a divisor of the number that divides it completely without leaving any remainder.

Given equation is 4x^3+10x^2 – 6x. This can be factorized as given below.

4x^3+10x^2-6x = 0

We take the common term 2x, then,

2x ( 2x^2 + 5x -3)=0

2x ( 2x^2 +6x -x -3)=0

2x (2x (x+3) -1(x+3))=0

2x (2x-1)(x+3)=0

Hence we can conclude that the factors of the given equation are 2x(x+3)(2x – 1). Option B shows the correct factors.

To know more about the factors, follow the link given below.

brainly.com/question/3423184.

6 0
3 years ago
What are two ratios that are equivalent to 1:1
kow [346]

Equivalents to 1:1 -

2:2

3:3

4 0
3 years ago
Read 2 more answers
Lacy draws a diamond from a standard deck of 52 cards. Without replacing the first card, she then proceeds to draw a second card
Viktor [21]

Answer:

a) i) No

ii) Probability of drawing a diamond and then spade without replacement is 0.0637.

b) i) Yes

ii) Probability of drawing a diamond and then spade with replacement is 0.0625

Step-by-step explanation:

Part a) Without replacement:

i) Are these events independent?

No, because the both events are dependent. because a card taken out of the deck is not replaced back before taking out the other card so the chances of event occur change.

ii) Determine the probability of drawing a diamond and then a spade without replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after taking diamond = 52 -1 =51

Spades = 13

Probability of drawing a spade  = 13/51

Probability of drawing a diamond and then spade = 13/52 * 13/51

= 169/2652

=0.0637

So, Probability of drawing a diamond and then spade without replacement  is 0.0637

Part b) With replacements

i) Are these events independent?

Input Yes or No:

Yes, these events are independent because a card taken out of the deck is replaced back before taking out the other card so the chances of event occur doesn't change.

ii) Determine the probability of drawing a diamond and then a spade with replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after replacing diamond = 52

Spades = 13

Probability of drawing a spade  = 13/52

Probability of drawing a diamond and then spade = 13/52 * 13/52

= 169/2704

=0.0625

So, Probability of drawing a diamond and then spade with replacement is 0.0625

7 0
4 years ago
PLEASE HELP URGENT!!!
spin [16.1K]

Answer:

0.70

Step-by-step explanation:

According to the given question,

P(A) = 0.60

P(B) = 0.25

P(A and B) = 0.15

And we are asked to find P(A or B) ,

We know,

  • P(A or B) = P(A) + P(B)-P(A and B)

Putting the values we get,

  • P(A or B) = 0.60 + 0.25 - 0.15

  • P(A or B) = 0.70

Thus option B is correct one.

5 0
4 years ago
Answerrrrrr If anyone knows just reply
lina2011 [118]

Answer:

C ) 6 units

Step-by-step explanation:

I' just guessing but based off of the other one is 4 then this must be at least 4.

6 0
2 years ago
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