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telo118 [61]
2 years ago
13

2+2 Please help I’ve been try this all day long

Mathematics
2 answers:
Alika [10]2 years ago
6 0

Answer:

4

Step-by-step explanation:

LOL

sesenic [268]2 years ago
5 0

Answer:

the answer is 4!!!!!!!!!!!!!!

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D=7.9cm. what is the circumference and area of the circle?
In-s [12.5K]
Circumfrence: pi times diameter
7.9*\pi
circumfrence is approximatley 24.806

area: \pi r^2
a=\pi*(1/2(d))^2
a= 48.99
8 0
3 years ago
Read 2 more answers
Solve the problem:
stepan [7]

volume of the box is 675 cubic inches

A machine produces open boxes using square sheets of plastic.

It is a square sheet so length and width are same

Lets assume length as x so width is also x

The machine cuts equal-sized squares measuring 3 inches on a side from each corner of the sheet.

After turning up the sides the height of the box becomes 3 inches

We know the volume of a box formula

Volume = Length * width * height

We know length is  x , width is x  and height = 3

So V = x * x * 3

Given volume = 675 cubic inches

675 = x * x * 3

675 = x^2* 3

Divide by 3 on both sides

225 = x^2

Now we take square root on both sides

x = 15

the length of one side of the open box is 15 inches.



5 0
3 years ago
Can someone help me with number 3 pls
sergejj [24]

Answer:

hypothesis

Step-by-step explanation:

If <em>hypothesis</em> then <em>conclusion</em>

5 0
3 years ago
Consider this figure. Enter the measure of
kotykmax [81]

Step-by-step explanation:

4x + 7x + 2° = 90° { being complementary angles }

11x = 90° - 2°

11x = 88°

x = 88° / 11

x = 8°

<YVZ = <em>7</em><em> </em><em>*</em><em> </em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>2</em><em>°</em><em> </em><em>=</em><em> </em><em>5</em><em>8</em><em>°</em>

<em>Hope </em><em>it </em><em>will </em><em>help </em><em>:</em><em>)</em>

3 0
3 years ago
Read 2 more answers
Since at t=0, n(t)=n0, and at t=∞, n(t)=0, there must be some time between zero and infinity at which exactly half of the origin
Airida [17]
Answer: t-half = ln(2) / λ ≈ 0.693 / λ

Explanation:

The question is incomplete, so I did some research and found the complete question in internet.

The complete question is:

Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:

N(t)=No e−λt,

where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.

Part (A) Since at t=0, N(t)=No, and at t=∞, N(t)=0, there must be some time between zero and infinity at which exactly half of the original number of nuclei remain. Find an expression for this time, t half.

Express your answer in terms of N0 and/or λ.

Answer:

1) Equation given:

N(t)=N _{0} e^{-  \alpha  t} ← I used α instead of λ just for editing facility..

Where No is the initial number of nuclei.

2) Half of the initial number of nuclei: N (t-half) =  No / 2

So, replace in the given equation:

N_{t-half} =  N_{0} /2 =  N_{0}  e^{- \alpha t}

3) Solving for α (remember α is λ)

\frac{1}{2} =  e^{- \alpha t} &#10;&#10;2 =   e^{ \alpha t} &#10;&#10; \alpha t = ln(2)

αt ≈ 0.693

⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ




4 0
3 years ago
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