1/2-5/6 can someone help me

Mathematics

2 answers:

weqwewe [10]2 years ago

6 0

Answer:

-1/3

Step-by-step explanation:

answer is -1/3

aleksandr82 [10.1K]2 years ago

3 0

Exact Form:

-1/3

Decimal Form:

-0.3 (with a line over the 3)

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Frank has recentlybstarted living a healthier lifestyle . He originally weighed 230 and a half pounds . Now he weighs 198 and th

Ksivusya [100]

Answer:

31 9/10

Step-by-step explanation:

if u want to find out how many pounds u lose u subtract 230 1/2 by 198 3/5

230 5/10 minus 198 6/10

31 9/10

hope this ehlps

5 0

2 years ago

Read 2 more answers

Match each description to the appropriate provider or service.

lys-0071 [83]

Explanation:

Urgent care centers: care for basic needs after regular doctor hours

Hospitals: treat time-sensitive emergencies

Medical specialists: offer treatment in a specific field of medicine, such as cardiology

General practice doctors and nurse practitioners: care for routine medical needs

Crisis pregnancy centers: provide counseling for unplanned pregnancies

Discussion

Urgent care centers are often open all hours, but may not be as fully equipped (or staffed) to provide the sort of emergency medicine that a fully-equipped hospital can provide. While a general- or nurse-practitioner can provide routine care, they will consult with specialists when expertise is needed in a specific area.

Various kinds of pregnancy centers can provide counseling and perhaps some medical services for planned or unplanned pregnancies.

6 0

2 years ago

Solve this query plzzz

Olin [163]

Step-by-step explanation:

$\frac{\sin \:4A}{\cos \:2A} \times \frac{1 - \cos \:2A}{1 - \cos\:4A} = \tan \:A \\ \\ LHS = \frac{\sin \:4A}{\cos \:2A} \times \frac{1 - \cos \:2A}{1 - \cos\:4A} \\ \\ = \frac{2\sin \:2A.\cos \:2A}{\cos \:2A} \times \frac{1 - (2 { \cos}^{2}A - 1) }{1 - (2 { \cos}^{2}2A - 1) } \\ \\ = 2\sin \:2A \times \frac{1 - 2 { \cos}^{2}A + 1}{1 - 2 { \cos}^{2}2A + 1 } \\ \\ = 2\sin \:2A \times \frac{2- 2 { \cos}^{2}A }{2 - 2 { \cos}^{2}2A } \\ \\ = 2\sin \:2A \times \frac{2(1 - { \cos}^{2}A) }{2 (1- { \cos}^{2}2A) } \\ \\ = 2\sin \:2A \times \frac{1 - { \cos}^{2}A}{1- { \cos}^{2}2A } \\ \\ = 2\sin \:2A \times \frac{ { \sin}^{2}A}{{ \sin}^{2}2A } \\ \\ = 2 \times \frac{ { \sin}^{2}A}{{ \sin}2A } \\ \\ = 2 \times \frac{ { \sin}^{2}A}{{ 2\sin}A. \cos \: A } \\ \\ = \frac{ { \sin}A}{ \cos \: A } \\ \\ = tan \: A \\ \\ = RHS \\$