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3 years ago

If u can answer all of these I will give u brainlest

Mathematics

2 answers:

zavuch27 [327]3 years ago

3 0

B <
C =
D >
E >
F >
G <
I <
J <
K <
L >
M <

wlad13 [49]3 years ago

3 0

Answer:

2.<

3.=

4.=

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7.>

9.=

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13.=

Step-by-step explanation:

You might be interested in

James wants to enlarge a photograph that is 6 inches wide and 4 inches tall so that it fits into the frame shown above. How tall

Andrej [43]

You would set up a proportion 6/4 = 30/x you then can do what i call the fish and multiply 30 by 4 and the divide by 6 which will give you x which your answer is 20

4 0

4 years ago

three pigs entered a race around a track. piggly takes 6 minutes to run one lap. piglet takes 3 minutes to run one lap and it ta

madreJ [45]

6 minutes, 3 minutes, 5 minutes
we need to find the lowest common multiple of these numbers.

6 : 6,12,18,24,30
3: 3,6,9,12,15,18,21,24,27,30
5: 5,10,15,20,25,30

30 is ur lowest common multiple...so they will all meet at the starting point in 30 minutes...hooray for piggly, piglet, and wiggly :)

8 0

4 years ago

Ann and betty together have $60. Ann has $9 more than twice Bettys amount. How much do each have?

Lesechka [4]

Answer:

Ann: $43
Betty: $17

Step-by-step explanation:

Let b represent the amount Betty has. Then Ann has 2b+9 and together, they have ...

b + (2b+9) = 60

3b = 51 . . . . . . . . . subtract 9

b = 17 . . . . . . . . . . divide by 3

Betty has $17 and Ann has the other $43 of the total of $60.

5 0

3 years ago

Read 2 more answers

Which set of points does NOT represent a function?

Reptile [31]

Answer:

OC is not a function

Step-by-step explanation:

It's not a function because the x cannot repeat.

6 0

4 years ago

Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

Answer:

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form $ay''+by'+cy=0$ .

Given: $y''+y'+y=0$

Let $y=e^{rt}$ be it's solution.

We get,

$\left ( r^2+r+1 \right )e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2+r+1=0$

{ we know that for equation $ax^2+bx+c=0$ , roots are of form $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ }

We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

For two complex roots $r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta$ , the general solution is of form $y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )$

i.e $y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Applying conditions y(0)=1 on $e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$ , $c_1=1$

So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

$y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )$

Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

Therefore,

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

3 0

3 years ago