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Free_Kalibri [48]
3 years ago
14

When x = 10, what type of solution do we have?

Mathematics
2 answers:
zloy xaker [14]3 years ago
6 0
One solution because when x=10 it one solution and when 2=2 it many solutions
Gennadij [26K]3 years ago
5 0

Answer:

one solution

Step-by-step explanation:

One solution

ex: x=10

No solution

ex: x=x

Many solutions

ex: 3x+2y=5

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Points A and B lle in plane R. line AB does not lle in plane R.<br> sometimes<br> always<br> never​
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Answer: The answer is never

Step-by-step explanation: The question has been presented in a complicated manner. I am answering the question based on my understanding. Line AB will never lie in plane R. The correct option among all the options that are given in the question is the third option. I hope that this is the answer that has come to your desired help.

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kenny6666 [7]

Answer:

f(x) =  \frac{x + 7}{6 - x}  \\  \frac{3}{2}  =  \frac{x + 7}{6 - x}  \\ 3(6 - x) = 2(x + 7) \\ 18 - 3x = 2x + 14 \\  - 3x - 2x = 14 - 18 \\  - 5x =  - 4 \\  \frac{ - 5x}{ - 5}  =   \frac{ - 4}{ - 5}  \\ x =  \frac{4}{5}

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the expression 12(x+4) represents the total number of CDs Mie bought in April and May at $12 each. Which property is applied to
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Let A fa, b,c. B [a, b, d), and C tb, d,e. Find the union of A and B, and then the union of this with C. Also, find the union of
Andre45 [30]

Answer:  A ∪ B = {a, b, c, d}

               (A ∪ B) ∪ C =  = {a, b, c, d, e}

               B ∪ C =  = {a, b, d, e}

               (B ∪ C) ∪ A  =  = {a, b, c, d, e}

<u>Step-by-step explanation:</u>

A = {a, b, c}       B = {a, b, d}         C = {b, d, e}

Union means "to join" so combine the sets to form a union.

A ∪ B = {A & B}

         = {a, b, c & a, b, d}

         = {a, b, c, d}          <em>because we do not need to list a & b twice</em>

(A ∪ B) ∪ C = {(A ∪ B) & C)

                  = {a, b, c, d & b, d, e}

                  = {a, b, c, d, e}     <em>because we do not need to list b & d twice</em>

<em />

B ∪ C = {A & B}

         = {a, b, d & b, d, e}

         = {a, b, d, e}           <em>because we do not need to list b & d twice</em>

<em />

(B ∪ C) ∪ A = {(B ∪ C) & A)

                  = {a, b, d, e & a, b, c}

                  = {a, b, c, d, e}     <em>because we do not need to list a & b twice</em>

<em />

<em />

4 0
3 years ago
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