If the temperature after 4.4 degree Celsius drop was -2.5 degree Celsius, ° was the temperature at noon
<u>Step-by-step explanation:</u>
Here we have , If the temperature after 4.4 degree Celsius drop was -2.5 degree Celsius . We need to find what was the temperature at noon . Let's find out:
Let us suppose that initially we have temperature x° , So the temperature after 4.4 degree Celsius drop was -2.5 degree Celsius , i.e.
⇒
Adding 4.4 both sides:
⇒
⇒
⇒ °
Therefore , If the temperature after 4.4 degree Celsius drop was -2.5 degree Celsius, ° was the temperature at noon .
Answer:
Each playground will be 100 m2. Both playgrounds are 200 m2.
Area of square is defined by a × a.
a = length of side. In this case a is 10 m
So, Area = 10 m × 10m
Area = 100 m2 (square meters). This is the area of one playground.
Two playgrounds will be the double, 200 m2
Step-by-step explanation:
Amount of increase = 20-12 = 8
Percentage increase = 8/12 = 0.666... 66.666...% ≈ 67%
Answer:
the value of 2 in 0.812 is 2 thousandths/0.002
0.002 = 2/1000
0.812 = 812/1000
Answer: 1. False. [∠XFG is lying between the one side and the line extended to the next side of the triangle, therefore it is an exterior angle.]
2.True. [∠EFG is lying between the two sides of the ΔEFG, therefore it is an interior angle of the triangle]
3.True. [∠FEZ is lying between the one side and the line extended to the other side of ΔEFG ]
4.False. [∠YGE is a straight line it is between the one side and the line extended to the same side ∴ it cannot be an exterior angle of the triangle ]
5. True.[∠EGF and FGY together make a straight line therefore they are supplementary angles]
6.False.[∠FEG and ∠FGE are both the interior angles of a triangle and we know that for supplementary angles they should lie on the same line or together make a straight line]