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Lady bird [3.3K]
3 years ago
14

please help please help please please please please please please please please please please please please please please please

please please please please please please please please please please please please please please please please please please please please please please please don't wanna fail my test please help please help please​

Mathematics
1 answer:
7nadin3 [17]3 years ago
3 0
Answer:
1) -10^3 (-10 to the power of 3)
2) r^5 (pie to the power of 5)
3) 1/2^2 + x^3 (1/2 to the power of 2 + x to the power of 3)
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Helppppppppppppppppppppppppppppppppppppp
ipn [44]

[ a⁵ (a²b³)⁵ ] / [ a²b⁻² ]

[ a⁵ (a¹⁰b¹⁵) ] / [ a²b⁻² ]

[ a⁵⁰ b⁷⁵ ] / [ a²b⁻² ]

I think this: a⁴⁸b⁷⁷ is the answer.

Hope this helps :)


5 0
4 years ago
Will give brainliest
klio [65]

Answer:

Area of the parallelogram =base×height

area of parallelogram =3cm×2cm

area of parallelogram = 6cm²

8 0
3 years ago
Solve the equation for x and enter your answer in the box below.
ivolga24 [154]

Answer:

x=65

Step-by-step explanation:

this is the answer

3 0
3 years ago
Read 2 more answers
I d k man<br> here something easy<br> x + 5 = 10<br> x = ?
d1i1m1o1n [39]

Answer:

x = 5

Step-by-step explanation:

x + 5 = 10

<u>    -5     -5</u>

x = 5

<em><u>Hope this helped! Have a nice day! Plz mark as brainliest!!!</u></em>

<em><u>-XxDeathshotxX</u></em>

7 0
3 years ago
Find four consecutive integers whose sum is 682.
Vitek1552 [10]
Because they're consecutive, it means that the first one is x, the second one is x+1, the third one is x+2 (x+1+1), and the fourth one is x+3. Because we're given that the sum of all of them is 682, just add all of them together:
x+(x+1)+(x+2)+(x+3)=682
x+x+x+x+1+2+3=682
4x+6=682
4x+6-6=682-6
4x=676
x=676/4
x=169
Thus, the consecutive integers are: 169, 170, 171, 172
5 0
3 years ago
Read 2 more answers
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