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3 years ago

Please help please send me the one that you sent me and I sent it to her and I

Mathematics

1 answer:

Rudiy273 years ago

8 0

Answer:

This is wrong.

Step-by-step explanation:

You didnt give enough detail.

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helpppppppppppppppp need now--------------------------------------------------Manuel borrowed $1,500 from his bank and signed a

Sedaia [141]

Answer: I think it’s 225
Explanation: 1,500 • .15= 225

3 0

3 years ago

The perimeters of the triangles shown below are equal

Naya [18.7K]

Answer:

x=19

Step-by-step explanation:

The perimeter of the right triangle is

P=9+12+15 =36

The perimeter of the left triangle is

P =x-7+ x-7+ x-7 = 3x-21

Set them equal

36 = 3x-21

Add 21 to each side

36+21 = 3x-21+21

57 = 3x

Divide each side by 3

57/3 = 3x/3

19 =x

6 0

3 years ago

Read 2 more answers

Malorie took out a loan to build a deck.The loan was for $15000 and had a 7.5% simple interest rate. If she paid a total of $1,6

attashe74 [19]

Answer:

The final value (FV) that is paid in a loan (which is the sum of the capital and the interests) equals the present value (PV) of the loan multiplied by $(1+i\times{n})$ , in a simple interest context, where "n" equals the periods of time and "i" equals the interest rate valid for that periodicity.
Then $FV=PV\times(1+i\times{n})$ . In this case, PV=$15,000; final value equals FV=$15,000+1,687.5= $16,687.5.
We should clear "n" from our equation, which means: $16,687.5=15,000\times(1+n\times0.075)$ . Dividing both sides by 15,000, then subtracting 1 both sides, and finally dividing by 0.075 both sides, results in n=1.5.
Then, Malorie had the loan for one an a half periods.

3 0

3 years ago

Which value is equivalent to (7x5x2/7x3)^2 x (5^0/2^-3)^3 x2^-9?

koban [17]

Answer:

100/9

Step-by-step explanation:

(7*5*2/7*3)² * (5^0/2^-3)³ * 2^-9

Solution:

We know that any number with power 0 = 1

(7*5*2/7*3)² * (1/2^-3)³ * 2^-9

Now cancel out 2 by 2

= (7*5*2/7*3)² * (1/1^-3)³ * 1^-9

=(70/21)² * (1)³/(1^-3)³ * 1^-9

=(10/3)^2 * 1/1^-1 * 1/1^9

=100/9 *1 *1

=100/9....

7 0

3 years ago

What is the interquartile range of the data set?

anastassius [24]

The interquartile range of the data set will be 30.

Explanation

Given data set: { 40, 48, 62, 60, 62, 40, 25, 50, 20, 30, 55 }

First we will rearrange the data in numeric order. So...

{ 20, 25, 30, 40, 40, 48, 50, 55, 60, 62, 62 }

Here the middle value in the set is 48. So, the median is 48 and it is diving the whole set into two different data sets. The median of the first set is 30 and median of the second set is 60.

That means, Lower quartile(Q₁) = 30 and Upper quartile(Q₃) = 60

So, the interquartile range of the data set: IQR= Q₃ - Q₁ = 60 - 30 = 30

6 0

3 years ago