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3 years ago

So, I have a question if anyone can answer soon.

Mathematics

1 answer:

Sonja [21]3 years ago

7 0

Answer:

You're right must be a different problem

Step-by-step explanation:

You know this, but just to verify:

1. Find Common Denominator:

6 15/21 - 6 7/21

2. Subtract

6 15/21 - 6 7/21 = 8/21 feet

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PLS HELPPPP ITS PROB EASY BUT I HAVE SO MANY LATE WORK TO DO:)))

kumpel [21]

Answer:

It’s C

Step-by-step explanation:

4 0

3 years ago

Find out the answers to this

meriva

Answer:

$\tan \theta = - \frac{1}{5} = - 0.2$

$\cos \theta = 0.98$

$\sin \theta = - 0.196$

Step-by-step explanation:

It is given that $\cot \theta = - 5$ and $\theta$ is in the fourth quadrant.

So, only $\cos \theta$ will have positive value and $\sin \theta$ , $\tan \theta$ will have negative value.

Now, $\cot \theta = - 5$

⇒ $\tan \theta = \frac{1}{\cot \theta} = -\frac{1}{5}$ (Answer)

We know, that $\sec^{2} \theta - \tan^{2} \theta = 1$

⇒ $\sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019$

{Since, $\cos \theta$ is positive then $\sec \theta$ will also be positive}

⇒ $\cos \theta = \frac{1}{\sec \theta} = \frac{1}{1.0198} = 0.98$ (Answer)

We know, that $\csc^{2} \theta - \cot^{2} \theta = 1$

⇒ $\csc \theta = - \sqrt{1 + \cot^{2} \theta } = - \sqrt{1 + (- 5 )^{2} } = - 5.099$

{Since, $\sin \theta$ is negative then $\csc \theta$ will also be negative}

⇒ $\sin \theta = \frac{1}{\csc \theta} = \frac{1}{- 5.099} = - 0.196$ (Answer)

4 0

3 years ago

Can someone help me I'm so confused

nikklg [1K]

A is the correct answer. A coefficient is just a number that appears in front of a variable. Please note that a number that doesn't have a variable behind it is still a coefficient since there is technically a variable behind it with a power of 0.

4 0

4 years ago

Read 2 more answers

Can someone explain to me how to solve these ?

boyakko [2]

$\bf 21)\\\\
\cfrac{c}{a}=r+d\implies \cfrac{c}{r+d}=a
\\\\\\
23)\\\\
ka=v+w\implies a=\cfrac{v+w}{k}
\\\\\\
25)\\\\
z=y+mx\implies z-y=mx\implies \cfrac{z-y}{m}=x$

8 0

4 years ago

Given that tan θ ≈ 1.072, where 0 < θ < , 2 π find the values of sin θ and cos θ.

anygoal [31]

Answer:

The answer to your question is

sin Ф = 0.731 and sinФ = -0.731; cos Ф 0.682 and cos Ф = -0.682

Step-by-step explanation:

tan Ф = 1.072, 0 < Ф < 2 π, tan Ф is positive, find the solution in the first and third quadrangle.

- tan Ф = opposite side / adjacent side

- 1.072 / 1 = opposite side / adjacent side

- opposite side = 1.072 and adjacent side = 1

Calculate hypotenuse

c² = a² + b²

c² = 1.072² + 1²

c² = 2.149

hypotenuse = c = 1.466

First quadrangle

sin Ф = 1.072 / 1.466 = 0.731

cos Ф = 1 / 1.466 = 0.682

Third quadrangle

sin Ф = -1.072 / 1.466 = -0.731

cos Ф = -1 / 1.466 = -0.682

5 0

3 years ago