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Arlecino [84]
3 years ago
9

It costs a general admission fee of $6 to get into the fair and then $1 for each ride. Which of the following equations would re

present the total cost to ride x rides at the fair?
Mathematics
1 answer:
joja [24]3 years ago
5 0

Answer:

6+1x=y

Step-by-step explanation:

-just add 6 because you will only pay it once to enter the fair

-place x for the number of rides the person gets on and 1 next to it to multiply

- place Y at the end because we don't know how much the person spent

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I really need helppppp
Dmitry [639]

Answer: the distance of the boat from the foot of the lighthouse is 290.5 feet.

Step-by-step explanation:

The right angle triangle ABC representing the scenario is shown in the attached photo.

Angle A is alternate to the angle of depression, hence, they are the same.

The height of the lighthouse represents the opposite side of the right angle triangle. The distance, x of the boat from the foot of the lighthouse represents the adjacent side of the right angle triangle.

To determine x, we would apply

the tangent trigonometric ratio.

Tan θ, = opposite side/adjacent side. Therefore,

Tan 11.1 = 57/x

x = 57/Tan 11.1 = 57/0.1962

x = 290.5 feet to the nearest tenth.

6 0
3 years ago
A circle with radius 3 has a sector with a central angle of 60.<br> What is the area of the sector?
CaHeK987 [17]

Answer:

Sector area = (central angle / 360) * PI * radius^2

Sector area = (1/6) * PI * 3^2

Sector area = 9/6 * PI

Sector area = 4.7123889804

Step-by-step explanation:

6 0
3 years ago
Fill in the space to complete to equality:<br><br> 3v-v²=v(__)
levacccp [35]

Answer:

3v-v² = v(3-v)

Step-by-step explanation:

Use distributive property on the right side of the equality.

6 0
3 years ago
An article reports that 1 in 500 people carry the defective gene that causes inherited colon cancer. In a sample of 2000 individ
Tema [17]

Answer:

a) P=0.558

b) P=0.021

Step-by-step explanation:

We can model this random variable as a Poisson distribution with parameter λ=1/500*2000=4.

The approximate distribution of the number who carry this gene in a sample of 2000 individuals is:

P(x=k)=\frac{\lambda^ke^{-\lambda}}{k!} =\frac{4^ke^{-4}}{k!}

a) We can calculate that the approximate probability that between 4 and 9 (inclusive) as:

P(4\leq x\leq 9)=\sum_{k=4}^9P(k)\\\\\\ P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\P(9)=4^{9} \cdot e^{-4}/9!=262144*0.0183/362880=0.013\\\\\\

P(4\leq x\leq 9)=\sum_{k=4}^9P(k)=0.195+0.156+0.104+0.060+0.030+0.013=0.558

b) The approximate probability that at least 9 carry the gene is:

P(x\geq9)=1-P(x\leq 8)\\\\\\

P(0)=4^{0} \cdot e^{-4}/0!=1*0.0183/1=0.018\\\\P(1)=4^{1} \cdot e^{-4}/1!=4*0.0183/1=0.073\\\\P(2)=4^{2} \cdot e^{-4}/2!=16*0.0183/2=0.147\\\\P(3)=4^{3} \cdot e^{-4}/3!=64*0.0183/6=0.195\\\\P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\

P(x\geq9)=1-P(x\leq 8)\\\\P(x\geq9)=1-(0.018+0.073+0.147+0.195+0.195+0.156+0.104+0.060+0.030)\\\\P(x\geq9)=1-0.979=0.021

8 0
3 years ago
Allison and her classmates planted bean seeds at the same time as Yuki and her classmates in Tokyo did. Allison is video-chattin
fomenos

Answer:

yukis plant

Step-by-step explanation:

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2 years ago
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