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3 years ago

Please help. I dont understand it

Mathematics

2 answers:

11Alexandr11 [23.1K]3 years ago

7 0

Answer:

Step-by-step explanation:

nexus9112 [7]3 years ago

4 0

Answer:

Yea I got 32

Step-by-step explanation:

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In the figure below, triangle JKL is isosceles, with JK LK, and triangle LMN is equilateral.

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Graph the image of this triangle after a dilation with a scale factor of 2 centered at the origin.

Svet_ta [14]

Answer:

Since, the coordinates of the given triangle are (0,0), (4,-4) and (-4,-2)

In the dilation by the scale factor k with centered at origin,

$(x,y)\rightarrow (kx,ky)$

Thus, If the dilation occurs by the scale factor of 2 with centered at origin,

New coordinates of the triangles are,

$(0,0)\rightarrow (2\times 0, 2\times 0)$

$(-4,4)\rightarrow (2\times -4, 2\times 4)$

$(-4,-2)\rightarrow (2\times -4, 2\times -2)$

Thus, the coordinates of new triangle are,

(0,0) ( -8, 8) and (-8,-4)

7 0

3 years ago

A small garden measures 9 ft by 13 ft. A uniform border around the garden increases the total area to 192 ft square. What is the

victus00 [196]

The width of border is 1.5 feet

<h3><u>Solution:</u></h3>

Given that small garden measures 9 ft by 13 ft

A uniform border around the garden increases the total area to 192 ft square

To find: width of border

Let the width of border be "x"

Then the new measures of garden are (9 + 2x) feet and (13 + 2x) feet

The total area of garden = 192 square feet

$(9 + 2x)(13 + 2x) =192$

$117 + 18x + 26x + 4x^2 = 192\\\\4x^2 + 44x - 75 = 0$

<em><u>Let us solve the above equation by quadratic formula</u></em>

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Using the above formula,

For $4x^2 + 44x - 75 = 0$ , we have a = 4 ; b = 44 ; c = -75

Substituting the values of a = 4 ; b = 44 ; c = -75 in above quadratic formula we get,

$\begin{aligned}&x=\frac{-44 \pm \sqrt{44^{2}-4(4)(-75)}}{2 \times 4}\\\\&x=\frac{-44 \pm \sqrt{1936-1200}}{8}\\\\&x=\frac{-44 \pm \sqrt{3136}}{8}\\\\&x=\frac{-44 \pm 56}{8}\end{aligned}$

$\begin{aligned}&x=\frac{-44+56}{8} \text { or } x=\frac{-44-56}{8}\\\\&x=\frac{12}{8} \text { or } x=\frac{-100}{8}\\\\&x=1.5 \text { or } x=-12.5\end{aligned}$

Since "x" cannot be negative,

we get x = 1.5

Thus width of border is 1.5 feet

4 0

3 years ago

Please help. I dont understand it ​

Please help. I dont understand it