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disa [49]
3 years ago
10

PLEASE HELP FAST

Mathematics
1 answer:
Minchanka [31]3 years ago
6 0

Answer:

-3165

Step-by-step explanation:

put 3 in for x than you just multiply from there than once you multiplied add and subtract than you have the answer

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A triangular pyramid has a height of 9 yards and a base with an area of 24 square yards. What is the volume of the pyramid?
HACTEHA [7]

Answer:

1728 yds

Step-by-step explanation:

7 0
3 years ago
Need help please stressing out over this problem!?!?!
ludmilkaskok [199]

v =  \frac{4}{3} \times \pi \times  {r}^{3}

Finding the radius,

d = 2r, \: r =  \frac{d}{2}  =  \frac{8}{2}  = 4inches

Plugging in our values,

v =  \frac{4}{3}  \times 3.14 \times  {4}^{3}  =  \frac{4}{3}  \times 3.14 \times 64 = 267.95 {inches}^{3}  \\

Rounding to the nearest whol number,

v = 268 {inches}^{3}

6 0
3 years ago
Please help! In the question you have to find whether the number is either rational or irrational.
Mnenie [13.5K]

Answer:

Square root of 30 is irrational because the answer is a non-terminating decimal.

4/7 is rational because it is a fraction.

21 divided by the square root of 4 is irrational because the result is a non-terminating decimal.

Pi is irrational because it's a non-terminating decimal.

-27 is rational because rational numbers can be positive or negative.

I hope this is correct! :-)

4 0
3 years ago
Marylou buys a package of 50 jewels to decorate 4 different pair of jeans.She uses the same number of jewels on each pair of jea
Molodets [167]

She can use 12 jewels for each pair of jeans. In fact, using 12 jewels per jeans implies that she will use 12 \cdot 4 = 48 jewels. The two remaining jewels can't be used on any pair of jeans, otherwise she wouldn't use the same number of jewels for each jeans.

This derives from the fact that, if you divide 50 by 4, you get a result of 12 with a remainder of 2.

6 0
3 years ago
WILL MARK BRAINLIEST
Fantom [35]

Answer:

StartFraction 25 Over 9 EndFraction

Step-by-step explanation:

\bigg(  \huge{\frac{ {3}^{2}a ^{ - 2}  }{3 {a}^{ - 1} }} \bigg)^{k}  \\  \\  =  \bigg(  \huge{\frac{ 9a   }{3 {a}^{ 2} }} \bigg)^{k}  \\  \\  = \bigg(  \huge{\frac{ 3   }{ {a}}} \bigg)^{k}  \\  \\  = \bigg(  \huge{\frac{ 3   }{ {5}}} \bigg)^{ - 2}   \\  \\  = \bigg(  \huge{\frac{ 5   }{ {3}}} \bigg)^{ 2}  \\  \\  =   \huge{\frac{ 25   }{ {9}}}

3 0
4 years ago
Read 2 more answers
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