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vichka [17]
3 years ago
10

Is the line through points P(2,-9) and Q(6, -13) perpendicular to the line through points R(5,-1) and

Mathematics
1 answer:
Kay [80]3 years ago
8 0
Line through P(0, 5) and Q(-1, 8):
slope = m = (y2 - y1) / (x2 - x1) = (8 - 5) / (-1 - 0) = 3 / -1 = -3

line through R(3, 3) and S(5, -1):
slope = m = (y2 - y1) / (x2 - x1) = (-1 - 3) / (5 - 3) = -4 / 2 = -2

Parallel lines have equal slopes. Since the two lines have different slopes, they are not parallel.
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309×29 solve it by using regrouping and partial products
Alina [70]
8961
309 \times 29
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3 years ago
Find the exact value of sin(255∘)
Masteriza [31]

Check the picture below.

\textit{Sum and Difference Identities} \\\\ sin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(255^o)\implies sin(135^o+120^o) \\\\\\ sin(135^o)cos(120^o)~~ + ~~cos(135^o)sin(120^o) \\\\\\ \left( \cfrac{\sqrt{2}}{2} \right)\left( -\cfrac{1}{2} \right)~~ + ~~\left( -\cfrac{\sqrt{2}}{2} \right)\left( \cfrac{\sqrt{3}}{2} \right)\implies -\cfrac{\sqrt{2}}{4}~~ - ~~\cfrac{\sqrt{6}}{4}\implies \cfrac{-2-\sqrt{6}}{4}

5 0
2 years ago
Simplify each exponential expression using the properties of exponents and match it to the correct answer.
saveliy_v [14]

1) (2\times3^-2)^3 (5\times3^2)^2 / (3^-2)(5\times2)^2 = 2

2) (3^3) (4^0)^2 (3\times2)^-3 (2^2) = 1/2

3) (3^7\times4^7) (2\times5)^-3 (5)^2 / (12^7) (5^-1) (2^-4) = 2

4) (2.3)^-1 (2^0) / (2.3)^-1 = 1

<u>Step-by-step explanation</u>:

Step 1 :

(2\times3^-2)^3 (5\times3^2)^2 / (3^-2)(5\times2)^2

⇒ (2^3) (3^-6) (5^2) (3^4) / (3^-2) (10^2)

⇒ (2.2^2.5^2) (3^-6.3^4) / (3^-2) (10^2)

⇒ (2)(10^2) (3^-2) / (3^-2) (10^2)

⇒ 2

Step 2 :

(3^3) (4^0)^2 (3\times2)^-3 (2^2)

Any number with power 'zero' is 1.

⇒ (3^3) (1^2) (3^-3) (2^-3) (2^2)

⇒ (2^(-3+2))

⇒ 2^-1 = 1/2

Step 3 :

(3^7\times4^7) (2\times5)^-3 (5)^2 / (12^7) (5^-1) (2^-4)

⇒ (12^7) (2^-3) (5^-3) (5^2) / (12^7) (5^-1) (2^-4)

⇒ (12^7) (2^-3) (5^-3) (5^2) / (12^7) (5^-1) (2^-4)

⇒ (2^-3) (5^(-3+2)) / (5^-1) (2^-4)

⇒ (2^-3) (5^-1) / (5^-1) (2^-4)

⇒ 1 / (2^-1)

⇒ 2

Step 4 :

(2.3)^-1 (2^0) / (2.3)^-1

⇒ (2^0)

⇒ Any number with power 'zero' is 1

⇒ 1

8 0
3 years ago
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Sindrei [870]
We start with 3: it stays unchanged

3.


then the first decimal place also remains unchanged:

3.6


now the second decimal place:


3.61

does it remain unchanged? No! the number AFTER is is 5 or bigger (it's 7), so we need to round it up. the answer is this:

3.62
5 0
3 years ago
10 fish are in a tank, 3 fish drown, how many fish are left?
taurus [48]
10. Fish don't drown (; nice try tho
6 0
3 years ago
Read 2 more answers
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