Answer:
28 hours
Step-by-step explanation:
Adena, Julius, and Tia volunteered to read to children at the public library.
Let us represent, the number of hours worked by
Adena = x
Julius = y
Tia = z
Julius worked two hours less than Tia.
y = z - 2
z = y + 2
Adena worked twice as many hours as Julius.
x = 2y
Altogether they worked 58 hours.
x + y + z = 58.... Equation 1
We substitute 2y for x and y + 2 for z in Equation 1
2y + y + y + 2 = 58
4y + 2 = 58
Collect like terms
4y = 58 - 2
4y = 56
y = 56/4
y = 14
We are the find the number of hours Adena worked which is represented by x
Note that:
x = 2y
y = 14, hence,
x = 2 × 14
x = 28 hours
Therefore, the number of hours Adena worked is 28 hours
Answer:
<h2>x = 1</h2>
Step-by-step explanation:

The solution to given system of equations are (x, y) = (4, 2)
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
2x + 3y = 14 ---------- eqn 1
3x - 4y = 4 --------- eqn 2
We have to solve the given system of equations
We can solve the above system of equations by elimination method
<em><u>Multiply eqn 1 by 3</u></em>
3(2x + 3y = 14)
6x + 9y = 42 --------- eqn 3
<em><u>Multiply eqn 2 by 2</u></em>
2(3x - 4y = 4)
6x - 8y = 8 ----------- eqn 4
<em><u>Subtract eqn 4 from eqn 3</u></em>
6x + 9y = 42
6x - 8y = 8
( - ) --------------
9y + 8y = 42 - 8
17y = 34
<h3>y = 2</h3>
<em><u>Substitute y = 2 in eqn 1</u></em>
2x + 3(2) = 14
2x + 6 = 14
2x = 14 - 6
2x = 8
<h3>x = 4</h3>
Thus the solution to given system of equations are (x, y) = (4, 2)
Answer:
The entropy change AS, for an ideal gas is given by: dt V Where T is the thermodynamic temperature, V is the volume and R=8.314. Determine the entropy change when a gas expands from 1 litre to 3 litres for a temperature rise from 100K to 400K given that: Cv = 45 + 6 x 10-T + 8 x 10-6T2 b) The average value of a complex voltage waveform is given by: V = ( 10 (10sin ox +3sin 30x +2 sin 508) dt Evaluate Vav correct to 2 decimal places.
1 is 96 because you must do the inverted T