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MA_775_DIABLO [31]

3 years ago

12

Two boys, Shawn and Curtis, went for a walk. Shawn began walking 20 seconds earlier than Curtis. Shawn walked at a speed of 5 fe

et per second. Curtis walked at a speed of 6 feet per second. For how many seconds had Sean been walking at the moment on the two boys had walked exactly the same distance?

1 answer:

Alexeev081 [22]3 years ago

5 0

Distance = speed * time
for curtis d = st = 6t (where t is the time that he walks)
sean walks 20 seconds longer than curtis so we have the equation

d = s(t+20) = 5(t+20)

as the distances are the same we have

So sean has walked 100+20 = 2

6t = 5(t+20)
6t = 5t + 100
t = 100
so Sean walks 120 seconds when they had both walked the same distance.

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