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3 years ago

A ribbon is 1.28 meters long. A rope is 2.34 meters longer than the ribbon. How long

Mathematics

1 answer:

satela [25.4K]3 years ago

5 0

Answer:

4.02m

Step-by-step explanation:

carry 1 1

1 . 2 8

+ 2 . 7 4

4 . 0 2

just add the two given numbers

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Johnny spend 1/7 of his income on Food, 1/10 of his income on gas, and 3/8 of his income on rent. What percentage of his income

Agata [3.3K]

Answer:

38.2%

Step-by-step explanation:

1/7 ≈ 14.29%

1/10 = 10.00%

3/8 = 37.50%

The total that Johnny has allocated for food, gas, and rent is ...

14.29% + 10.00% + 37.50% = 61.79%

So, the remaining amount is ...

100% -61.79% = 38.21%

About 38.2% of Johnny's income remains.

7 0

3 years ago

help me on the following, in the picture IK U WANT THE POINTS JUST HELLPPP , ONLY IF UKNOW THE ANSWER/ NO LINKS and swrong answe

earnstyle [38]

Answer:

any coordinate outside the parabola is a reasonable answer.

Step-by-step explanation:

test the solution (0, 0) and if if that number is greater than 0 then the rest of the points outside on the inside are.

x = 0

y = 0

(0)^2 - 2(0) - 3 = -3

-3 is less than 0 so (0, 0) is not a possibility so any coordinate outside the parabola is a reasonable answer.

3 0

3 years ago

Which number is an integer? -34 -0.4 0.4 3.4 PLS HELP I'M TIMED EDGE 2020

Stella [2.4K]

Answer:

Step-by-step explanation: The four numbers: - 34, -0.4, 0.4, 3.4

so if you look at it it The answer is -34

7 0

3 years ago

Read 2 more answers

What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t

weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

$A=LW$

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

$L=BC\\W=AB$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the points

$A(2,-1),B(5,2),C(12,-5),D(9,-8)$

Find out the distance BC

we have

$B(5,2),C(12,-5)$

substitute in the formula

$d=\sqrt{(-5-2)^{2}+(12-5)^{2}}$

$d=\sqrt{(-7)^{2}+(7)^{2}}$

$d_B_C=\sqrt{98}\ units$

Find out the distance AB

we have

$A(2,-1),B(5,2)$

substitute in the formula

$d=\sqrt{(2+1)^{2}+(5-2)^{2}}$

$d=\sqrt{(3)^{2}+(3)^{2}}$

$d_A_B=\sqrt{18}\ units$

Find out the area

$A=(L)(W)$

we have

$L=d_B_C=\sqrt{98}\ units$

$W=d_A_B=\sqrt{18}\ units$

substitute

$A=(\sqrt{98})(\sqrt{18})=42.0\ units^2$

4 0

3 years ago

What is the width (or height) of the parking lot?

Gre4nikov [31]

The width is 146.0315533981 cuz 12033÷82.4 is 146.0315533981

6 0

3 years ago