1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
CaHeK987 [17]
3 years ago
8

A recipe calls for 2 cups of butter for every 5 cups of flour. Question 1 Part A What is the ratio of flour to butter? Write the

ratio in three different ways. Do not simplify the ratios. Enter the correct answers in the boxes.
Mathematics
1 answer:
grandymaker [24]3 years ago
3 0

Answer:

The answer is 5:2 5 to 2 5/2.

You might be interested in
A class has 36 students in it and 25% of the students wore hats to school. What fraction of the students wore hats?​
Setler79 [48]

Hi,

25/100 * 36 = 9

So it represents 9/36 = 1/4 of students

8 0
3 years ago
Part A
Vika [28.1K]
I think the answer is 36π square inches, hope that help MLG  M8
6 0
3 years ago
Y=3/5 +2 plot the slope of the line
Ipatiy [6.2K]
The slope is equal to ³/₅.

6 0
3 years ago
I have the answer what is the steps
gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

6 0
3 years ago
The attached Excel file 2013 NCAA BB Tournament shows the salaries paid to the coaches of 62 of the 68 teams in the 2013 NCAA ba
PSYCHO15rus [73]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The attached Excel file 2013 NCAA BB Tournament shows the salaries paid to the coaches of 62 of the 68 teams in the 2013 NCAA basketball tournament (not all private schools report their coach's salaries). Consider these 62 salaries to be a sample from the population of salaries of all 346 NCAA Division I basketball coaches.

Question 1. Use the 62 salaries from the TOTAL PAY column to construct a 95% confidence interval for the mean salary of all basketball coaches in NCAA Division I.

xbar = $1,465,752

SD = $1,346,046.2

lower bound of confidence interval ________

upper bound of confidence interval _______

Question 2. Coach Mike Krzyzewski's high salary is an outlier and could be significantly affecting the confidence interval results. Remove Coach Krzyzewski's salary from the data and recalculate the 95% confidence interval using the remaining 61 salaries.

xbar = $1,371,191

SD = $1,130,666.5

lower bound of confidence interval _________

upper bound of confidence interval. ________

Answer:

Question 1:

lower bound of confidence interval = $1,124,027

upper bound of confidence interval = $1,807,477

Question 2:

lower bound of confidence interval = $1,081,512

upper bound of confidence interval = $1,660,870

Step-by-step explanation:

Question 1:

The sample mean salary of 62 couches is

 \bar{x} = 1,465,752

The standard deviation of mean salary is

 s = 1,346,046.2

The confidence interval for the mean salary of all basketball coaches is given by

 $ CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $

Where \bar{x} is the sample mean, n is the sample size, s is the sample standard deviation and  t_{\alpha/2} is the t-score corresponding to a 95% confidence level.  

The t-score corresponding to a 95% confidence level is  

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025  

Degree of freedom = n - 1 = 62 - 1 = 61

From the t-table at α = 0.025 and DoF = 61

t-score = 1.999

So the required 95% confidence interval is  

CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\CI = 1,465,752 \pm 1.999 \cdot (\frac{1,346,046.2}{\sqrt{62} } ) \\\\CI = 1,465,752 \pm 1.999 \cdot (170948.04 ) \\\\CI = 1,465,752 \pm 341,725 \\\\LCI = 1,465,752 - 341,725 = 1,124,027 \\\\UCI = 1,465,752 + 341,725 = 1,807,477\\\\

Question 2:

After removing the Coach Krzyzewski's salary from the data

The sample mean salary of 61 couches is

\bar{x} = 1,371,191

The standard deviation of the mean salary is

s = 1,130,666.5

The t-score corresponding to a 95% confidence level is  

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025  

Degree of freedom = n - 1 = 61 - 1 = 60

From the t-table at α = 0.025 and DoF = 60

t-score = 2.001

So the required 95% confidence interval is  

CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\CI = 1,371,191 \pm 2.001 \cdot (\frac{1,130,666.5}{\sqrt{61} } ) \\\\CI = 1,371,191 \pm 2.001 \cdot (144767 ) \\\\CI = 1,371,191 \pm 289,678.8 \\\\LCI = 1,371,191 - 289,678.8 = 1,081,512 \\\\UCI = 1,371,191 + 289,678.8 = 1,660,870\\\\

6 0
3 years ago
Other questions:
  • At a party 70 people are right handed and 12 people are left handed. What is the ratio of right handed people to the total numbe
    15·1 answer
  • Find the volume of the rectangular prism
    14·2 answers
  • What is the value of x to the nearest tenth?
    11·1 answer
  • What’s the square root of 10 to the nearest thousandth
    8·1 answer
  • Which of the following points represents the center of a circle whose
    11·2 answers
  • Convert these improper fractions to mixed numbers 74 over 3 please help
    7·1 answer
  • Determine where the function is increasing, decreasing, and constant.
    9·2 answers
  • If your good at math please help me
    5·2 answers
  • If the temperature drops from 7f to -17f how much did the temperature decrease​
    8·2 answers
  • Please help I’m not good at triangle angles
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!