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yan [13]
2 years ago
9

I need help please...

Mathematics
1 answer:
KonstantinChe [14]2 years ago
3 0

Answer:

i think your answer would be $38.60

Step-by-step explanation:

i hope its right

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Abigail and her mom are back-to-school shopping at new Navy . Select items are on sale at 43% off their regular price . What is
vaieri [72.5K]

Answer:

$12.54

Step-by-step explanation:

First, you have to apply the sale to the original price. In this case, you would have to multiply 22 and 43% to get $9.46. Now, you have to subtract 9.46 from 22 to get 12.54.

7 0
3 years ago
Inequality<br><br> Show your step by step solution to this.<br><br> 5-2x&gt;17
bonufazy [111]

<u><em>Answer: x<-6 *The answer should be the negative sign.*</em></u>

Step-by-step explanation:

subtraction property of equality is subtracting the same number from both sides of an equation does not change the equation.

subtract 5 both sides of an equation.

5-2x-5>17-5

simplify.

-2x>12

multiply by -1 both sides of an equation.

(-2x)(-1)<12(-1)

simplify.

2x<-12

divide by 2 both sides of an equation.

2x/2<-12/2

-12/2=-6

12/2=6

6*2=12

12/6=2

x<-6

Hope this helps!

Thanks!

Have a great day!

3 0
3 years ago
Pls help with 29..tank you
trapecia [35]

Answer:

See below

Step-by-step explanation:

Let the  2 roots be  A and A^2.

Then A^3 = c/a and A + A^2 = -b/a.

Using the identity a^3 b^3 = (a + b)^3 - 3ab^2 - 3a^2b:-

A^3 + (A^2)^3 =  ( A + A^2)^3 - 3 A.A^4 - 3 A^2. A^2

= (A + A^2)^3 - 3A*3( A + A^2)

Substituting:-

c/a + c^2/a^2 = (-b/a)^3 - 3 (c/a)(-b/a)

Multiply through by a^3:-

a^2c + ac^2 = -b^3 + 3abc

Factoring:-

ac(a + c) = 3abc - b^3

This is not the formula required in the question but let's see if the formula in the question reduces to this. If it does we have completed the proof.

a(c - b)^3 = a(c^3 - 3c^2b + 3cb^2 - b^3) = ac^3 - 3ac^2b + 3acb^2 - ab^3

c(a - b)^3 = c(a^3 - 3a^2b + 3ab^2 - b^3) = ca^3 - 3a^2bc + 3acb^2 - cb^3.

These are equal so we have

ca^3 - 3a^2bc + 3acb^2 - cb^3 = ac^3 - 3abc^2 + 3acb^2 - ab^3

The 3acb^2 cancel out so we have:-

a^3c - ac^3 =  3a^2bc - 3abc^2 + b^3c - ab^3

ac(a^2 - c^2) = 3abc( a - c) + b^3(c - a)

ac(a + c)(a -c) = 3abc(a - c) - b^3 (a - c)

Divide through by (a - c):-

ac(a + c) = 3abc - b^3 , which is the result we got earlier.

This completes the proof.

 

3 0
3 years ago
Read 2 more answers
3 csc^2(2x) + 2 cosec 2x = 1-cot^2(2x)
asambeis [7]

I am assuming you want to solve for x:-

Now cosec^2 2x = 1 - cot^2 2x  so the equation becomes

3 cosec^2(2x) + 2 cosec 2x =  cosec^2 2x

2 cosec^2 2x + 2 cosec 2x = 0

2 cosec 2x (  cosec 2x + 1) = 0

so 2 cosec 2x = 0  or    cosec 2x = -1

cosec 2x = 0  or cosec 2x = -1

cosec 2x = 0  is indeterminate so we ignore the first one

cosec 2x = -1  can be written as 1 / sin 2x = -1

so sin 2x = -1  

giving 2x = 270 degrees

Therefore  x = 135 degrees  answer


3 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP when u answwer dont come bck tho
Bumek [7]
C

For negatives the higher the number the lower it is…
6 0
2 years ago
Read 2 more answers
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