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Helen [10]
2 years ago
15

Let g(x)= - x^2 + 5x + 2, find and simplify g(-3)​

Mathematics
1 answer:
ollegr [7]2 years ago
3 0

Answer:

g(-3) = -4

Step-by-step explanation:

We are given the following function:

g(x) = -x^2 + 5x + 2

Find and simplify g(-3)

We want to find the value of g when x = -3. So

g(-3) = (-3)^2 + 5(-3) + 2 = 9 - 15 + 2 = -4

g(-3) = -4

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ki77a [65]
This will come out to 35.1

Hope this helps ya!

7 0
3 years ago
A day of the week is randomly chosen. What is the probability of choosing monday or friday?
Karo-lina-s [1.5K]

Answer:

You have a 2/7ths chance of picking Monday or Friday.

Explanation

There are 7 days of the week so you have a 2 out of 7 chance of picking Monday or Friday

8 0
3 years ago
Read 2 more answers
Find the 10th term of the geometric sequence whose common ratio is 2/3 and whose first term is 3.
Sergeu [11.5K]

Answer:

\frac{512}{6561}

Step-by-step explanation:

1) if according to the condition a₁=3 and r=2/3, then a₁₀ can be calculated as:

a₁₀=a₁*r⁹;

2) according  to the rule above:

a₁₀=3*(2/3)⁹=512*3/(6561*3)=512/6561.

5 0
2 years ago
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

5 0
3 years ago
Can someone help me solve this
Scrat [10]

Answer:

your photo dose not work

Step-by-step explanation:

but you would half to email it to me then i can help you if you want to do that

8 0
3 years ago
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